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lara [203]
3 years ago
9

Consider the reaction below. HI + H2O mc014-1.jpg H3O+ + I– Which is an acid-conjugate base pair? HI and H2O H2O and H3O+ H3O+ a

nd I– HI and I–
Chemistry
2 answers:
lesya692 [45]3 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

According to Bronsted-Lowry, species which donate a proton are known as acid. The species which accept a proton are known as a base.

In the given reaction, acids and bases are as follows.

    HI  +   H_{2}O \rightarrow    H_{3}O^{+}           +         I^{-}

 Acid        Base     Conjugate acid   Conjugate base

Therefore, the acid HI loses a proton to form a conjugate base that is I^{-}.

Thus, we can conclude that HI and I^{-} is an acid conjugate base pair.

earnstyle [38]3 years ago
3 0

Answer:

Then the correct answer is d HI and I-

Explanation:

Hello! Let's solve this!

According to bronsted-Lowry, the conjugate acid is what forms after a base accepts a proton. A conjugate base is the one formed after the acid accepts a proton.

In this problem we have the conjugate acid that is H3O +, the acid is HI, the conjugate base is I- and the base is H2O

Reaction     HI   +   H2O    ---->   H3O+    +   I-

Then the correct answer is d HI and I-

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Storage solution; deionized water; stabilizes.

Explanation:

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8 0
3 years ago
Based on the structure, which material will dissolve this biomolecule the best? dilute alcohol water oil ionic solution
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6 0
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What is the limiting reactant if 12 moles of p4 react with 15 moles of o2?.
brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

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4 0
2 years ago
Zn +
saul85 [17]

Answer:

1. Theoretical yield = 2.03g

2. Actual yield 1.89g

Explanation:

Let us write a balanced equation. This is illustrated below:

Zn + 2HCI —> ZnCl2 + H2

Molar Mass of HCl = 1 +35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 2 x 36.5 = 73g

Molar Mass of H2 = 2x1 = 2g/mol

1. From the equation,

73g of HCl produced 2g of H2.

Therefore, 74g of HCl will produce = (74 x 2)/73 = 2.03g

Therefore, theoretical yield = 2.03g

2. %yield = 93%

Theoretical yield = 2.03g

Actual yield =?

%yield = Actual yield /Theoretical yield x100

Actual yield = %yield x theoretical yield

Actual yield = 93% x 2.03 = (93/100)x2.03 = 1.89g

Actual yield =1.89g

4 0
3 years ago
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