Answer:
a) T=549.36N Upwards
b) T=448.56N Upwards
c) T=650.16N Upwards
Explanation:
The very first thing we can do to solve this problem is to draw a free body diagram we can use to analyze the situation (see attached picture).
On the diagram we can see there are only two forces acting on the object: the tension of the rope and the weight of the object itself.
a)
Since the object is moving at a constant speed, this means that its acceleration will be zero. So we can do a sum of forces like this:
T-W=0
T=W
T=mg
T=549.36N upwards
b)
For part b, since the object is accelerating downwards, we wil say that it's acceleration is negative, so
so we can do a sum of forces again:
so
T-W=ma
T=ma +W
T=ma+mg
T=m(a+g)
and now we substitute:
which yields:
T=448.56N upwards (in this particular case, the tension always goes upwards)
c)
Since the object is moving upwards, we can say that its acceleration will be positive, so
we can take the solved equation we got on the previous part of the problem, so we get:
T=m(a+g)
which yields:
T=650.16N upwards
False. The sun from earth looks yellow, orange, or sometimes red, but it is really a big white ball of fire.
Answer:
If you meant 2.34, 2.34 meters = 23.4 decimeters.
Formula: multiply the value in meters by the conversion factor '10'.
So, 2.34 meters = 2.34 × 10 = 23.4 decimeters.
Hope that helps. x
Answer: Your using your skeletal muscle
Explanation:
Answer:
a) v = √ 2gL abd b) θ = 45º
Explanation:
a) for this part we use the law of conservation of energy,
Highest starting point
Em₀ = U = mg h
Final point. Lower
Em₂ = ½ m v²
Em₀ = Em₂
m g h = ½ m v²
v = √2g h
v = √ 2gL
b) the definition of power is the relationship between work and time, but work is the product of force by displacement
P = W / t = F. d / t = F. v
If we use Newton's second law, with one axis of the tangential reference system to the trajectory and the other perpendicular, in the direction of the rope, the only force we have to break down is the weight
sin θ = Wt / W
Wt = W sin θ
This force is parallel to the movement and also to the speed, whereby the scalar product is reduced to the ordinary product
P = F v
The equation that describes the pendulum's motion is
θ = θ₀ cos (wt)
Let's replace
P = (W sin θ) θ₀ cos (wt)
P = W θ₀ sint θ cos (wt)
We use the equation of rotational kinematics
θ = wt
P = Wθ₀ sin θ cos θ
Let's use
sin 2θ = 2 sin θ cos θ
P = Wθ₀/2 sin 2θ
This expression is maximum when the sine has a value of one (sin 2θ = 1), which occurs for 90º,
2θ = 90
θ = 45º