set them equal to their sum. which in this case is 141 then solve for x and plug it into your original equation to get your answer.
Answer: The answer is 384 if your question is 12x1/2x64
The interval that f(x) is increasing is the distance from 200 to 300.
The minimum value of f(x) in the interval 0<x<300 is 200.
At a value of 500, the value of f(x) is 0.
The function can't be a quadratic function since there are two points in the graph where f(x) changes its rate from increasing to decreasing or the opposite. A quadratic function has only one of that point.
A. 6, 7, 8, 9
B. 2, 5, 8, 11
C. 5, 8, 13, 20
D. 3, 12, 27, 48
We have the following equation:
s = ut + 1 / 2at ^ 2
Clear a for the equation:
1 / 2at ^ 2 = s-ut
at ^ 2 = 2s-2ut
a = 2s / t ^ 2-2ut / t ^ 2
Rewriting:
a = (2s-2ut) / (t ^ 2)
Answer:
An equation that represents a in terms of other variables is:
C. 2s-2ut / t ^ 2