A youngster having a mass of 50.0 kg steps off a 1.00 m high platform. If she keeps her legs fairly rigid and comes to rest in 1
1 answer:
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Answer:
The maximum magnetic force is 2.637 x 10⁻¹² N
Explanation:
Given;
Power, P = 8.25 m W = 8.25 x 10⁻³ W
charge of the radiation, Q = 1.12 nC = 1.12 x 10⁻⁹ C
speed of the charge, v = 314 m/s
area of the conecntration, A = 1.23 mm² = 1.23 x 10⁻⁶ m²
The intensity of the radiation is calculated as;
The maximum magnetic field is calculated using the following intensity formula;
The maximum magnetic force is calculated as;
F₀ = qvB₀
F₀ = (1.12 x 10⁻⁹) x (314) x (7.497 x 10⁻⁶)
F₀ = 2.637 x 10⁻¹² N
Answer:
Explanation:
ri = 0.20cm
ro = 0.4 cm
length L = 13m
resistivity \rho = 2.00*10^13 ohm m
resistance can be determine by using following relation
Answer:
The tension in the string connecting block 50 to block 51 is 50 N.
Explanation:
Given that,
Number of block = 100
Force = 100 N
let m be the mass of each block.
We need to calculate the net force acting on the 100th block
Using second law of newton
We need to calculate the tension in the string between blocks 99 and 100
Using formula of force
We need to calculate the total number of masses attached to the string
Using formula for mass
We need to calculate the tension in the string connecting block 50 to block 51
Using formula of tension
Put the value into the formula
Hence, The tension in the string connecting block 50 to block 51 is 50 N.
The impulse is given by the magnitude of the force times the time interval:
We can see that the force F of the 4 skateboard is always the same (33 N), this means that the skateboard with greatest impulse is the one with the largest time interval, so skateboard C).
We can see that the force F of the 4 skateboard is always the same (33 N), this means that the skateboard with greatest impulse is the one with the largest time interval, so skateboard C).