A youngster having a mass of 50.0 kg steps off a 1.00 m high platform. If she keeps her legs fairly rigid and comes to rest in 1 0.0 ms, what is her momentum just as she hits the floor? What average force acts on her during the deceleration?
1 answer:
The average act on her during the deceleration is 4.47 meters per second.
<u>Explanation </u>:
<u>Given </u>:
youngster mass m = 50.0 kg
She steps off a 1.00 m high platform that is s = 1 meter
She comes to rest in the 10-meter second
<u>To Find </u>:
The average force and momentum
<u>Formulas</u> :
p = m * v
F * Δ t = Δ p
vf^2= vi^2+2as
<u>Solution </u>:
a = 9.8 m/s
vi = 0
vf^2= 0+2(9.8)(1)
vf^2 = 19.6
vf = 4.47 m/s .
Therefore the average force is 4.47 m/s.
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