Is it possible to have a copper-silver alloy of composition 20 wt% Ag- 80% Cu that, at equilibrium, consists of LaTeX: \alphaα a
nd liquid phases having mass fractions WLaTeX: \alphaα = 0.80 and WL= 0.20? If so, what will be the approximate temperature of the alloy? If such an alloy is not possible, explain why.
1 answer:
Answer:
800°C
Explanation:
Phase diagram of an alloy is a graphical presentation showing the phases compositions and their relative amounts at any different temperature and under equilibrium conditions. It is used to predict the phase changes of the alloys at different temperatures.
From the figure, we can see that the tie lines are proportional about α + L at a temperature of 800°C for
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Answer:
Explanation:
Previous concepts
Angular momentum. If we consider a particle of mass m, with velocity v, moving under the influence of a force F. The angular momentum about point O is defined as the “moment” of the particle’s linear momentum, L, about O. And the correct formula is:
Applying Newton’s second law to the right hand side of the above equation, we have that r ×ma = r ×F =
MO, where MO is the moment of the force F about point O. The equation expressing the rate of change of angular momentum is this one:
MO = H˙ O
Principle of Angular Impulse and Momentum
The equation MO = H˙ O gives us the instantaneous relation between the moment and the time rate of change of angular momentum. Imagine now that the force considered acts on a particle between time t1 and time t2. The equation MO = H˙ O can then be integrated in time to obtain this:
Solution to the problem
For this case we can use the principle of angular impulse and momentum that states "The mass moment of inertia of a gear about its mass center is ".
If we analyze the staritning point we see that the initial velocity can be founded like this:
And if we look the figure attached we can use the point A as a reference to calculate the angular impulse and momentum equation, like this:
And if we integrate the left part and we simplify the right part we have
And if we solve for we got:
