Given:

frequency, f = 60.0 Hz
frequency, f' = 45.0 Hz

Solution:
To calculate max current in inductor,
:
At f = 60.0 Hz


L = 0.1326 H
Now, reactance
at f' = 45.0 Hz:


Now,
is given by:
Therefore, max current in the inductor,
= 2.13 A
Mass and chemical composition
Answer:
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Explanation:
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Answer:
fracture will occur as the value is less than E/10 (= 22.5)
Explanation:
If the maximum strength at tip Is greater than theoretical fracture strength value then fracture will occur and if the maximum strength is lower than theoretical fracture strength then no fracture will occur.
![\sigma_m = 2\sigma_o [\frac{a}{\rho_t}]^{1/2}](https://tex.z-dn.net/?f=%5Csigma_m%20%3D%202%5Csigma_o%20%5B%5Cfrac%7Ba%7D%7B%5Crho_t%7D%5D%5E%7B1%2F2%7D)

= 15 GPa
fracture will occur as the value is less than E/10 = 22.5
Answer:
Both of them are wrong
Explanation:
The two technicians have given the wrong information about the wires.
This is because firstly, a higher rating of AWG means it is smaller in diameter. Thus, the diameter of a 18 AWG wire is smaller than that of a 12 AWG wire and that makes the assertion of the technician wrong.
Also, the higher the resistance, the smaller the cross sectional area meaning the smaller the diameter. A wire with bigger cross sectional area will have a smaller resistance
So this practically makes the second technician wrong too