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Fantom [35]
3 years ago
12

You are stopped at a red traffic light and are first in line at the intersection. When the traffic light changes to green, you s

hould
Accelerate quickly up to the speed limit.
Go, regardless of other traffic. You have the right-of-way.
Go, but only if the intersection is clear. Yield to pedestrians and vehicles still in the intersection.
Engineering
1 answer:
Ostrovityanka [42]3 years ago
8 0

Answer:

Go, but only if the intersection is clear.

Explanation:

Traffic at intersection can be complicated at times. If the green light comes on after a red light, you have the right of way to go, but you should be careful to only go when the intersection is clear to avoid an accident. Once using the road, a good driver should be conscious of the other road users, as accidents might happen from you claiming your-right of-way

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2 years ago
Unfiltered full wave rectifier with a 120 V 60 Hz input produces an output with a peak of 15V. When a capacitor-input filter and
Alborosie

Answer:

V_{pp}=2V

Explanation:

Source Voltage V= 120V

Frequency f=60Hz

Peak output voltage Vp=15V

Peak Output Voltage with filter V_p'=14V

Generally the equation for Peak to peak voltage is mathematically given by

V_p'=V_p-\frac{V_{pp}}{2}

Therefore

V_{pp}=2(V_p-v_p')

V_{pp}=2(15-14)

V_{pp}=2V

5 0
2 years ago
One kilogram of "as received" yard trimmings is made up of approximately 620 g moisture, 330 g of decomposable organic matter (r
Evgesh-ka [11]

Answer:

Explanation:

(a) Given that 620g moisture and 330g decomposable organic matter in yard trimming is represented by C₁₂.₇₆H₂₁.₂₈O₉.₂₆N₀.₅₄

Given the atomic mass of Carbon C = 12, Hydrogen H = 1, Oxygen O = 16 and Nitrogen N = 14

1 mole of trimming = 12*12.76 + 1*21.28 + 16*9.26 + 14*0.54

=  153.12 + 21.28 + 148.16 + 7.56

= 330.12 g/mol

which means 1 kg of as received trimming has 330 g of decomposable that produce 1 mole of decomposable

The moles of methane produced will be given as

m = (4a + b -2c - 3d)/8

= (4*12.76 + 21.28 - 2*9.26 - 3*0.54)/8

= (51.04 + 21.28 - 18.52 - 1.62)/8

= 52.18/8

= 6.5225

(b) Volume of methane V is given as

V = (0.0224 m³ CH₄mol/CH₄) × (6.5225 mol CH₄/ kg)

= 0.1461 m³ CH₄/kg lawn trimmings

(c) Energy will be given as

CH₄Energy = 6.5225 mol of CH₄/kg × 890 kJ/mol

= 5805.025

≈ 5805 kJ/kg

5 0
3 years ago
Water is the working fluid in an ideal regenerative Rankine cycle with one open feedwater heater. Superheated vapor enters the f
Zepler [3.9K]

Answer:

a) The net powered developed will be 145715 KW.

b) The rate of Heat Transfer to the steam passing through the boiler will be 326340 KW.

c) The thermal efficiency will be 0.45.

d) The mass flow rate will be 884.09 kg/s.

Explanation:

8 0
3 years ago
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