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tatuchka [14]
3 years ago
9

657 g of 2-chloro-2,4-dimethylpentane (g/mol = 134.65) is generated from a reaction between 2,4-dimethyl-2-pentanol (g/mol = 116

.20) and excess hcl. assuming 100% yield, how many grams of 2,4-dimethyl-2-pentanol were used?

Chemistry
1 answer:
jasenka [17]3 years ago
5 0
For a 100% yield 761.31 g of <span>2-chloro-2,4-dimethylpentane will be produced.</span>

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The balanced chemical equation for the reaction is as follows:

Pb(NO_{3})_{2}+2KI\rightarrow PbI_{2}+2KNO_{3}

From the molarity and volume of Pb(NO_{3})_{2} and KI, number of moles can be calculated as follows:

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For Pb(NO_{3})_{2} :

n=0.218 M\times 65\times 10^{-3}L=0.01417 mol

Similarly, for KI:

n=0.265 M\times 80\times 10^{-3}L=0.0212 mol

From the balanced chemical reaction, 1 mol of Pb(NO_{3})_{2} gives 1 mole of PbI_{2} thus, 0.01417 mol will give 0.01417 mol.

Molar mass of PbI_{2} is 461.01 g/mol, mass can be calculated as:

m=n\times M=0.01417 mol\times 461.01 g/mol=6.53 g

Similarly, 2 mol of KI gives 1 mole of PbI_{2} thus, 0.0212 mol will give \frac{0.0212}{2}=0.0106 mol of PbI_{2}.

Mass can be calculated as:

m=n\times M=0.0106 mol\times 461.01 g/mol=4.88 g

The amount of PbI_{2} obtained from KI is less than that from  Pb(NO_{3})_{2} thus, KI is limiting reactant and amount of PbI_{2} obtained from KI will be theoretical yield.

Actual yield is 3.26 g, % yield can be calculated as follows:

percentage yield=\frac{Actual yield}{theoretical yield}\times 100

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percentage yield=\frac{3.26 g}{4.88 g}\times 100=66.80%

Therefore, % yield will be 66.80%.

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