Answer: Volume would be 196.15 mL if the temperature were changed to 
and the pressure to 1.25 atmospheres.
Explanation:
Given: 
, 
= 256 mL,
= 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm
, 
Formula used to calculate volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to and the pressure to 1.25 atmospheres.
The by-product of the chlorination of an alkane is <u>HCl</u>
Explanation:
- Chlorination is the process of adding chlorine to drinking water to disinfect it and kill germs. Different processes can be used to achieve safe levels of chlorine in drinking water.
- Chlorination of alkane gives a mixture of different products.
- When consider mechanism of alkanes chlorination, free radicals are formed during the reaction to keep the continuous reaction.
- Different alkyl chloride compounds, extended carbon chains compounds and HCl are formed as products in product mixture.
- Chlorination byproducts, their toxicodynamics and removal from drinking water.
- Halogenated trihalomethanes (THMs) and haloacetic acids (HAAs) are two major classes of disinfection byproducts (DBPs) commonly found in waters disinfected with chlorine
- Chlorine is available as compressed elemental gas, sodium hypochlorite solution (NaOCl) or solid calcium hypochlorite (Ca(OCl)2
I don’t know I just want the points and plus o would never know I’m not even in high school
Explanation:
the experiment conducted is the student adds sugar to a cup of iced tea and a cup of hot tea. She notices that the time needed for the sugar to dissolve in each cup is different. She thinks this has something to do with the temperature of the tea
hypothesis: If the student puts the sugar in both glasses of tea, then the sugar in the hot tea should dissolve quicker.
Answer:
the answer is 74.03%
Explanation:
Add all the masses together, M of C = 120.1, M of H = 14.4 and M of N = 28.02. Adding all those together will give you the mass of the compound, then u divide the mass of carbon by the mass of compound and multiply by 100 to get the percent by mass.
120.1 + 14.4 + 28.02 = 162.26
120.1/162.26 x 100 = 74.03%
