Answer:5101.35v
Explanation:
Radius of gold nucleus=7.3×10-15m and a charge of +79e
Q= 79e
e=1.6×10^-19
q= +2e
The nucleus is considered as the point charge where the potential energy between the charges are
U = 1/(4×3.142×Eo)×(qQ)/r
Where r is distance between the charges and the nucleus
r=R+d
V=U/q
U= 1/(4×3.142×Eo)×Q/r
V= 1/(4×3.142×Eo)×Q/(r+d)
9.0×10^9 ×(79×10^-19)/(7.3×10^-15)+(1.5×10^-14)
V= 9.0×10^9 ×(1.264×10^-17)/(2.23×10^-14)
V= 9×10^9×(5.67×10^-14)= 5101.35v
Here I come and we wanna go home!!!
<span>Average velocity can be calculated by determining the total displacement divided by the total time of travel. The average velocity of an object does not tell us anything about what happens to it between the starting point and ending point. Average velocity is different from average speed because it considers the direction of travel and the overall change in position.</span>
Answer:
measure the vector diagram first
Answer:
Explanation:
4.95s≈5s
Use equation :
h=G*t²/2
h=120m ----hight of cliff
G=9.81m/s²
t=?
-----------------------
h=G*t²/2
120m=9.81m/s²*t²/2
240m=9.81m/s²*t²
t²=240m/ 9.81m/s²
t²=24.46s
t=√24.46s²
t=4.95 s≈5s
