All categories

3 years ago

Which energy output objects work with the turbine

Physics

1 answer:

viktelen [127]3 years ago

6 0

Answer:

The energy output object that works with the turbine is the alternator (generator)

Explanation:

In energy generation the turbine receives input energy from high pressured steam, high energy water etc. Which impinges and turn the blades of the turbine, this turbine is connected by means of a shaft to the alternator that converts the rotational motion of the shaft to electrical energy through Electro magnetic induction principles and also outputs the energy for consumption.

You might be interested in

Will mark as brainliest if correct!!!!!!!

lutik1710 [3]

C. A could be ruby (speed of light = 170,000 km/s); B could be diamond (speed of light = 120,000 km/s).

Explanation:

Refraction is a phenomenon that occurs when a light rays crosses the boundary between two different mediums.

When this occurs, the light wave changes speed and also direction, according to Snell's law:

$n_1 sin \theta_1 = n_2 sin \theta_2$ (1)

where

$n_1$ is the index of refraction of the first medium

$n_2$ is the index of refraction of the second medium

$\theta_1$ is the angle of incidence (the angle between the incident ray and the normal to the boundary)

$\theta_2$ is the angle of refraction (the angle between the refracted ray and the normal to the boundary)

The index of refraction is the ratio between the speed of light in a vacuum (c) and the speed of light in the medium (v):

$n=\frac{c}{v}$

Using this definition, we can rewrite eq.(1) as

$\frac{\sin \theta_2}{\sin \theta_1} = \frac{v_2}{v_1}$

Where $v_2$ is the speed of light in the 2nd medium and $v_1$ the speed of light in the 1st medium.

Now let's analyze the situation represented in the figure: we see that as the light ray enters the 2nd medium, it bends towards the normal, this means that the angle of refraction is smaller than the angle of incidence:

$\theta_2 < \theta_1$

This means that

$\frac{\sin \theta_2}{\sin \theta_1}$

And therefore,

$\frac{v_2}{v_1}$

So, the speed of light in the second medium is smaller than the speed of light in the first medium: this occurs only in option C), which is therefore the correct choice.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

6 0

4 years ago

An RLC circuit is composed of a 3.5 kΩ resistor, 1.1 nF capacitor and 7.6 mH inductor. If an AC 6.8 V rms is applied, what frequ

topjm [15]

Answer:

$5.5\times 10^{4}$ Hz

Explanation:

we know that the power is maximum in RLC circuit when inductive reactance and capacitive reactance are equal.

$C$ = Capacitance of the capacitor = 1.1 x 10⁻⁹ F

$L$ = Inductance of the inductor = 7.6 x 10⁻³ H

$f$ = frequency necessary for maximum power

$X_{C}$ = capacitive reactance = $\frac{1}{2\pi fC}$

$X_{L}$ = inductive reactance = $2\pi fL$

For maximum power :

$X_{L}$ = $X_{C}$

$2\pi fL$ = $\frac{1}{2\pi fC}$

$f = \frac{1}{2\pi \sqrt{LC}}$

$f = \frac{1}{2(3.14) \sqrt{(7.6\times 10^{-3})(1.1\times 10^{-9})}}$

$f =5.5\times 10^{4}$ Hz

7 0

3 years ago

To access his bank’s ATM, Tom must choose a four-digit PIN. Any digit from 0 through 9 can be used in the PIN, but digits may no

jenyasd209 [6]

The first digit can be any one of the 10 available digits.
. . . For each one . . .
The second digit can be any one of the 9 unused others.
. . . For each one . . .
The third digit can be any one of the 8 unused others.
. . . For each one . . .
The fourth digit can be any one of the 7 unused other.

So the total number of possible choices is

(10 x 9 x 8 x 7) = 5,040 possible PINs

3 0

3 years ago

Read 2 more answers

Water pollution can come from the _______ of dead organic matter or animal waste in waterways.

Lerok [7]

Water pollution can come from the remains of dead organic matter or animal waste in waterways

6 0

3 years ago

Read 2 more answers

A chain saw produces a spherical sound wave having a frequency of 214Hz in air at 358C (308.2K or 958F). At a distance of 600mm

Helen [10]

Given Information:

Frequency = 214 Hz

Temperature = 358° C = 308.2 K

Sound Pressure = p = 100 dB = 2 pascal

Distance = 600 mm = 0.60 m

Required Information:

(a) Acoustic Power Level = ?

(b) Acoustic Particle Velocity = ?

and Velocity level at a distance of 600 mm = ?

Answer:

Acoustic Power Level = Lw = 106.44 dB

Acoustic Particle Velocity = v = 0.0106 m/s

Velocity level = 60.25 dB

Explanation:

(a) Acoustic Power Level

Acoustic Power = W = 4πr² I

Acoustic Intensity = I = p ²/Z₀

Where Z₀ is the characteristic impedance of air Z₀ = 409.8 rayl

I = p ²/Z₀ = (2)²/409.8 = 0.00976 W/m²

W = 4πr² I = 4*π(0.60)²*0.00976 = 0.0441 W

Acoustic Power Level = Lw = 10log(W/Wref)

Where Wref is Reference Acoustic Power Wref = 1x10⁻¹² W

Lw = 10log(W/Wref) = 10log(0.0441/1x10⁻¹²) = 106.44 dB

Lw = 106.44 dB

(b) Acoustic Particle Velocity

Acoustic Particle velocity = v = p ²/Zs

Where Zs is specific acoustic impedance

Zs = Z₀kr/(1 + k²r²)⁰°⁵

Where k = 2πf/c and c = 346.1 m/s is the speed of sound in air

k = 2π*214/346.1 = 3.885 per m

Zs = 409.8*3.885*0.60/(1 + (3.885)²(0.60)²)⁰°⁵

Zs = 376.6 rayl

v = p ²/Zs = 2²/376.6 = 0.0106 m/s

v = 0.0106 m/s

Velocity level = 10log(v/vref) where vref = 10x10⁻⁹ m/s

Velocity level = 10log(0.0106/10x10⁻⁹) = 60.25 dB

Velocity level = 60.25 dB

8 0

4 years ago