Answer: The outside temperature is 262.1K or -10.9°C
Explanation:
Given that,
Original volume V1 = 2.75 L
Original temperature T1 = 20.0°C
Since unit of temperature is Kelvin, convert 20°C to Kelvin by adding 273 to 20°C
(20.0°C + 273K = 293K)
Outside volume V2 = 2.46 L
Outside temperature T2 = ?
Since volume and temperature are given while pressure is constant, apply the formula for Charle's law
V1/T1 = V2/T2
2.75L/293K = 2.46L/T2
To get the value of T2, cross multiply
2.75L x T2 = 2.46L x 293K
2.75LT2 = 720.78LK
Divide both sides by 2.75L
2.75LT2/ 2.75L = 720.78LK/2.75L
T2 = 262.1K
Hence, the outside temperature in Kelvin is 262.1K. Then, obtain outside temperature in Celsius by subtracting 273 from 262.1K
i.e 262.1K - 273 = -10.9°C
Thus, the outside temperature is 262.1K, or -10.9°C
