Answer:
30 g
Explanation:
<em>For CaCl₂</em>
3CaCl₂ + 2Na₃PO₄ ⟶ Ca₃(PO₄)₂ + 6NaCl
Moles of CaCl₂ = <em>c</em>×<em>V</em> = 5.0 × 10⁻² × 2.0 = 0.100 mol
Moles of Na₃PO₄ = 0.100 × 2/3 = 0.0667 mol
Mass of Na₃PO₄ = 0.0667 × 163.94 = 10.9 g
———————————————————
<em>For Mg(NO₃)₂
</em>
3Mg(NO₃)₂ + 2Na₃PO₄ ⟶ Mg₃(PO₄)₂ + 6NaCl
Moles of Mg(NO₃)₃ = <em>c</em>×<em>V</em> = 8.5 × 10⁻² × 2.0 = 0.170 mol
Moles of Na₃PO₄ = 0.170 × 2/3 = 0.113 mol
Mass of Na₃PO₄ = 0.113 × 163.94 = 1 g
—————————————————
Total mass of Na₃PO₄ = 10.9 + 18.6 = 29.5 g
To two significant figures, mass = 30 g
Answer: c12 has a mass of 12 amu
Explanation:
mass of one mole of c12 = g. So mass of 1 atom of c12 = 1.9927e-23g
Answer:
3: Lactone
Explanation:
Lactones are defined as carboxylic esters that contain the structure (−C(=O)−O−) which is essentially showing that an ester has now become part of the chemical structure of the ring.
Thus, looking at the question, it has the structure as defined in Lactones.
Thus, we can say that the compound is a Lactone.
<span>6.50x10^3 calories.
Now we have 4 pieces of data and want a single result. The data is:
Mass: 100.0 g
Starting temperature: 25.0°C
Ending temperature: 31.5°C
Specific heat: 1.00 cal/(g*°C)
And we want a result with the unit "cal". Now you need to figure out what set of math operations will give you the desired result. Turns out this is quite simple. First, you need to remember that you can only add or subtract things that have the same units. You may multiply or divide data items with different units and the units can combine or cancel each other. So let's solve this:
Let's start with specific heat with the unit "cal/(g*°C)". The cal is what we want, but we'ld like to get rid of the "/(g*°C)" part. So let's multiply by the mass:
1.00 cal/(g*°C) * 100.0 g = 100.0 cal/°C
We now have a simpler unit of "cal/°C", so we're getting closer. Just need to cancel out the "/°C" part, which we can do with a multiplication. But we have 2 pieces of data using "°C". We can't multiply both of them, that would give us "cal*°C" which we don't want. But we need to use both pieces. And since we're interested in the temperature change, let's subtract them. So
31.5°C - 25.0°C = 6.5°C
So we have a 6.5°C change in temperature. Now let's multiply:
6.5°C * 100.0 cal/°C = 6500.0 cal
Since we only have 3 significant digits in our least precise piece of data, we need to round the result to 3 significant figures. 6500 only has 2 significant digits, and 6500. has 4. But we can use scientific notation to express the result as 6.50x10^3 which has the desired 3 digits of significance. So the result is 6.50x10^3 calories.
Just remember to pay attention to the units in the data you have. They will pretty much tell you exactly what to add, subtract, multiply, or divide.</span>
The classification of the alcohols gives;
- Compound 1 - Primary alcohol
- Compound 2 - Tertiary alcohol
- Compound 3 - Secondary alcohol
- Compound 4 - Secondary alcohol
<h3>What are alcohols?</h3>
Organic compounds occurs in families. The family of compounds is called a homologous series. The homologous series always have a functional group. The functional group is the atom, group of atoms or bond that is responsible for the chemical reactivity of the members of a given homologous series.
Now we know that the alcohols are those organic compounds that contains the -OH group. The could be aliphatic or alicyclic compounds. We shall now proceed to name the kind of alcohols that each of the compounds shown are;
- Compound 1 - Primary alcohol
- Compound 2 - Tertiary alcohol
- Compound 3 - Secondary alcohol
- Compound 4 - Secondary alcohol
Learn ore about alcohols:brainly.com/question/4698220
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