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ycow [4]
4 years ago
9

During a collision that last 3 seconds, an object has its momentum changed by 3 kgm/s. What was the average Force acting on the

object (in Newtons) during this collision
Physics
1 answer:
ss7ja [257]4 years ago
4 0

Answer:

F = 1 N

Explanation:

Given,

Change in momentum = 3 kg m/s

time, t = 3 s

Force = ?

We know,

Force is equal to change in momentum per unit time.

F = \dfrac{\Delta P}{t}

F = \dfrac{3}{3}

F = 1 N

Hence, average force acting on the object during collision is equal to 1 N.

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Stolb23 [73]

Answer:

The current is  I_b  =  400 \ A

Explanation:

From the question we are told that

    The  length of the segment is  l  =  2.50  \  m

     The current is  I_a  =  1000 \ A

     The force felt is  F  =  4.0 \  N

        The distance of the second wire is  d =  5.0 \ cm  = 0.05 \  m

Generally the current on the second wire is mathematically represented as

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Here  \mu_o is the permeability of free space with value  \mu_o =  4 \pi * 10^{-7} \ N/A^2

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=>      I_b  =  400 \ A

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3 years ago
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