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Shalnov [3]
3 years ago
6

A ray of light traveling in water (n = 1.33) is incident at the flat surface of a block of glass (n = 1.60). If the incident ray

in water makes an angle of 36.6° with the normal to the interface, what angle does the ray that is refracted into the glass make with the normal?
Physics
1 answer:
Rudik [331]3 years ago
5 0

Answer:

θ₂ ≈ 29.7°

Explanation:

Given:

n₁ = 1.33, n₂= 1.60, θ₁ = 36.6°, θ₂ = ?

Solution:

According to snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1.33 × sin (36.6°) = 1.60 × sin θ₂

⇒ Sin θ₂ = 0.496

θ₂ ≈ 29.7°

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