<h3><u>Answer;</u></h3>
Mid-ocean ridges
<h3><u>Explanation</u>;</h3>
- Sea-floor spreading is the process by which molten material adds new oceanic crust to the ocean floor.
- Mid-ocean ridge is an undersea mountain chain where new ocean floor is produced at a divergent plate boundary.
- Mid ocean ridge occurs when convection currents rise in the mantle beneath the oceanic crust and create magma where two tectonic plates meet at a divergent boundary.
Answer:
1.11
Explanation:
The index of the medium can be calculated using below formula
V= c/ n ............eqn(1)
Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s
n= index of the medium
c= speed of light= 3 x 10^8 m/s
Substitute for the values in eqn(1)
2.7 x 10^8 = (3 x 10^8 m/s)/ n
Making " n" subject of the formula, we have
n= (3 x 10^8 )/(2.7 x 10^8)
n= 1.11
Hence, the index of the medium is 1.11
The strong magnetic fields is Long rang attractive power Reuther then week magnetic field.
Answer:
Option D
a new invention lowers the cost of production
Explanation:
When there is a new invention lowers the cost of production, the production is likely to increase since the time allocated is as previous. Therefore, the curve moves to the right, to indicate a positive direction
Answer:
The “terminal speed” of the ball bearing is 5.609 m/s
Explanation:
Radius of the steel ball R = 2.40 mm
Viscosity of honey η = 6.0 Pa/s



While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)

Substitute the given values to find "terminal speed"




The “terminal speed” of the ball bearing is 5.609 m/s