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Tpy6a [65]
3 years ago
7

The concentration of carbon monoxide (co) in an exhaust gas is 1x10^4 ppmv. what is the concentration in mg/m^3 at 25 and 1 atm

Engineering
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

1.1451 x 104 (11451.13)mg/m3

Explanation:

1 ppmv is defined as one volume of a contaminant or solid(CO)(mL) in 1 x 106 volume of solvent/water.

1ppmv = 1mL/m3

Concentration in mg/m3 = volume in ppm x molecular weight x pressure(kPa)/( gas constant x temperature(K)

Molecular weight of CO = 12 + 16

= 28g/mol

Temperature = 273.15 + 25

= 298.15K

Pressure = 1 x 101.325kPa

= 101.325kPa

Ppmv = 1 x 10-4ppmv

Gas constant, R = 8.3144 L.kPa/mol.K

Concentration in mg/m3 = (1 x 104 * 28 * 101.325)/(8.3144 * 298)

= 1.1451 x 104mg/m3

= 11451.13 mg/m3

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2 years ago
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Svetlanka [38]

Answer:

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6 0
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Which of the following sentences uses the active voice
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Write an ALP to separate odd and even numbers from an array of N numbers; arrange odd
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Below is the program to separate odd and even numbers                                  

<u>Explanation</u>:

<u>L1:</u>

         mov ah,00

         mov al,[BX]

         mov dl,al

         div dh

         cmp ah,00

         je EVEN1

         mov [DI],dl

         add OddAdd,dl

         INC DI

         INC BX

         Loop L1

         jmp CAL

    <u>EVEN1:</u>

         mov [SI],dl

         add Even Add,dl

         INC SI

         INC BX

         Loop L1

    <u>CAL:   </u>  

         mov ax,0000

         mov bx,0000

         mov al,OddAdd

         mov bl,EvenAdd

         MOV  ax,4C00h

         int 21h

end

The above program separates odd and even numbers from the array using 8086 microprocessor. It has odd numbers in 2000h and even numbers in 3000h.

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belka [17]

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