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3 years ago

Give reasons.A stone thrown upward returns back to the earth surface.

Physics

1 answer:

Wittaler [7]3 years ago

7 0

Answer:

Gravity

Explanation:

Due to earths gravity, anything that goes into the air returns back to the surface unless it is given the ability to fly.

Hope this helps!

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Two automobiles of equal mass approach an intersection. One vehicle is traveling with speed 13.0 m/s toward the east, and the ot

puteri [66]

Answer:

Explanation:

We shall apply law of conservation of momentum to know the Speed of northward moving vehicle before collision to check the veracity of driver's statement .

Let v be the velocity of composite mass after collision

Applying law of conservation of momentum in north direction

m v₂ = 2m v sin55.08

Applying law of conservation of momentum in east direction

m x 13 = 2m v cos55.08

Dividing these two equations

v₂ / 13 = tan55.08

v₂ = 13 tan55.08

= 18.62 m/s

= (18.62 x60 x 60) / 1000

= 67 km/h

= 67 x 5/8 mi/h

= 42 mi/h

So he is lieing.

7 0

4 years ago

4. There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is not

vampirchik [111]

The ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is the following:

$f = \frac{c}{\lambda}$

where

f is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

For the UVA, the range of wavelength is 320 nm - 400 nm, so

$\lambda_1 = 320 \cdot 10^{-9} m\\\lambda_2 = 400 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz\\f_2= \frac{3\cdot 10^8}{400\cdot 10^{-9}}=7.50\cdot 10^{14} Hz$

For the UVB, the range of wavelength is 280 nm - 320 nm, so

$\lambda_1 = 280 \cdot 10^{-9} m\\\lambda_2 = 320 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{280\cdot 10^{-9}}=1.07\cdot 10^{15} Hz\\f_2= \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz$

So the ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Learn more about waves, frequency and wavelength:

brainly.com/question/5354733

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#LearnwithBrainly

3 0

3 years ago

Please help :)

drek231 [11]

Answer:

Explanation: kinetic energy being transferred from one object to another. Kinetic energy is the energy of mass in motion. The kinetic energy of an object is the energy it has because of its motion.

8 0

3 years ago

Read 2 more answers

20. The goal of cognitive-behavioral therapy is BEST described as: A.improving the client's interactions with others. B.helping

Andre45 [30]

The goal of cognitive-behavioral therapy is BEST described as modifying the client's negative behavior and dysfunctional ways of thinking

What is cognitive-behavioral therapy ?

Talk therapy often used today is cognitive behavioural therapy (CBT) (psychotherapy). You engage in scheduled therapy sessions with a mental health professional (psychotherapist or therapist). To view difficult events more clearly and respond to them more effectively, CBT teaches you to become aware of false or negative thinking.

In order to assist people identify their most important goals and get through roadblocks, cognitive behavioral therapy (CBT) uses a time-sensitive, structured, present-oriented approach. The cognitive model, on which CBT is based, states that people's perceptions of situations have a stronger influence over their responses than the actual circumstances.

To know more about cognitive behavioral therapy use link below:

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#SPJ1

7 0

1 year ago

A bullet of mass 0.01 kg moving horizontally strikes a block of wood of mass 1.5 kg which is suspended as a pendulum. The bullet

jekas [21]

Answer:

423m/s

Explanation:

Suppose after the impact, the bullet-block system swings upward a vertical distance of 0.4 m. That's means their kinetic energy is converted to potential energy:

$E_p = E_k$

$mgh = mv^2/2$

where m is the total mass and h is the vertical distance traveled, v is the velocity right after the impact at, which we can solve by divide both sides my m

Let g = 9.81 m/s2

$gh = v^2/2$

$v^2 = 2gh = 2 * 9.81* 0.4 = 7.848$

$v = \sqrt{7.848} = 2.8m/s$

According the law of momentum conservation, momentum before and after the impact must be the same

$m_uv_u + m_ov_o = (m_u + m_o)v$

where $m_u = 0.01, v_u$ are the mass and velocity of the bullet before the impact, respectively. $m_ov_o$ are the mass and velocity of the block before the impact, respectively, which is 0 because the block was stationary before the impact

$0.01v_u + 0 = (0.01 + 1.5)*2.8$

$0.01v_u = 4.23$

$v_u = 4.23 / 0.01 = 423 m/s$

7 0

3 years ago

Give reasons.A stone thrown upward returns back to the earth surface.​

Give reasons.A stone thrown upward returns back to the earth surface.