Answer:
Explanation:
A chemical property describes the ability of a substance to undergo a specific chemical change.
A chemical reaction is a process that occurs when one or more substances are changed into one or more new substances.
Differences
Chemical properties are properties that can be observed or measured when a substance undergoes a chemical change.
Physical properties are properties that can be observed without bringing a chemical change.
Another one
chemical properties; can be used to predict how substances react.
chemical changes; It is mostly used in identifying or describing the substance.
Answer:
Part A: Hexacyanoferrate (III)
Part B: DiammintetraaquoCupperate (II)
Part C: Dichlorobis(ethylenediamine) Chromate (II)
Part D: Triaquocarbonylnickel (II) Sulphate
Part E: Potassium Dicarbonatedifluoroplatinate (II)
Explanation:
For naming the complex ions there is a specific rule
Nomenclature of the complex ions are as follow
- write a correct formulae
- Indicate the oxidation number of metal in the complex
- The oxidation number should write in the roman numeral in perenthasis after metal name
- Ligand named before the metal ion
- Ligan can be named in following order
* 1st negative, 2nd neutral, 3rd positive
* If there are more than 2 same charged ligand the write in
alphabetical order.
- Write prefix i.e di, tri, tetra for multiple monodentate ligands
- Anions name end at ido the replace the final name.
- Neutral ligands named as their usual name, but there are some exceptions such as
NH3 named as ammine
H2O names aqua or aquo
CO named ascarbonyl
NO named as nitrosyl
- If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
- The name of full complex will end with cation or anion with separate word.
Keeping the rules in mind the complexes named as following.
_________________________
Part A:
[Fe(CN)₆]³⁻
Name of the Complex : Hexacyanoferrate (III)
___________________
Part B:
[Cu(NH₃)₂(H₂O)₄]²⁺
Name of the Complex : DiammintetraaquoCupperate (II)
_______________________
Part C
CrCl₂(en)₂
Name of the Complex : Dichlorobis(ethylenediamine) Chromate (II)
________________________
Part C
[Ni(H₂O)₃(CO)]SO₄
Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate
______________________
Part E
K₄[Pt(CO₃)₂F₂]
Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)
The calculated pH is 3.79. therefore, the solution is acidic.
No, carbonic acid is not a strong acid. H2CO3 is a weak acid that dissociates into a proton (H+ cation) and a bicarbonate ion (HCO3- anion). This compound only partly dissociates in aqueous solutions.
H2 CO3 = H (+) + HCO3(-) Ka1 = 4.3 * 10^ -7
0.06 - x x x
Ka1 = x^2 / (0.06 - x) = 4.3 * 10^ - 7
A low Ka => x << 0.06 => 0.06 -x ≈ 0.06
=> Ka1 ≈ x^2 / 0.06 => x^2 ≈ 0.06 * Ka1 = 0.06 * 4.3 * 10^-7
=> x ≈ √ [ 2.58 * 10 ^ -8] = 1.606 * 10^ - 4 = 0.0001606
Second dissociation
HCO3(-) = H (+) + CO3(2-) Ka2 = 5.6 * 10^ - 11
0.0001606 - y y y
Ka2 ≈ y^2 / 0.0001606 => y = √ [0.0001606 * 5.6* 10^ -11]
y = 9.48 * 10^ -8
An acidic solution has a high concentration of hydrogen ions (H +start superscript, plus, end superscript), greater than that of pure water.
[H+] = x + y = 1.607 * 10^ -4
pH = - log [H+] = 3.79
Learn more about concentration here-
brainly.com/question/10725862
#SPJ4
Answer:
<h2>8.03 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer
<h3>8.03 g/mL</h3>
Hope this helps you
