Question

What is the energy in joules of a photon with a frequency of 3.16e 12 s-1?

Answer 1

Using equation:

E = hf

Where h = Planck's constant = 6.63 * 10⁻³⁴Js, f = frequency in s⁻¹

f = 3.16 * 10¹² s⁻¹

E =  6.63 * 10⁻³⁴ * 3.16 * 10¹²

E = 2.09508 * 10⁻²¹ J

That is the energy of the photon.

Hope this explains it.

Answer 2

We have: Energy(E) = Planck's constant(h) × Frequency(∨)
Here, Planck's constant(h) = 6.626 × 10⁻³⁴ J/s
Frequency (∨) = 3.16 × 10¹² /s

Substitute the values into the expression:
E = (6.626 × 10⁻³⁴)(3.16 × 10¹²) J
E = 2.093 × 10⁻²¹ Joules

In short, Your Final answer would be 2.093 × 10⁻²¹ J

Hope this helps!