Given the area, to rewrite the function using distributive property we get:
6(2x+5y)
using distributive property we open the parenthesis, this will give us:
6×2x+6×5y
simplifying the above we get
=12x+30y
Answer: 12x+30y
Answer: nickels = 14, dimes = 42, quarters = 18
<u>Step-by-step explanation:</u>
Let n represent nickels <em>which has a value of $0.05 </em>
Let d represent dimes <em>which has a value of $0.10</em>
Let q represent quarters <em>which has a value of $0.25</em>
It is given that:
n = n
d = 3n
q = n + 4
and their total value is $9.40 ⇒ n + d + q = $9.40
Use substitution to find the quantity of nickels:
.05(n) + .10(3n) + .25(n + 4) = 9.40
5n + 10(3n) + 25(n+4) = 940 <em>multiplied by 100 </em>
5n + 30n + 25n + 100 = 940 <em>distributed</em>
60n + 100 = 940 <em>added like terms</em>
60n = 840 <em>subtracted 100</em>
n = 14 <em>divided by 60</em>
n = 14
d = 3n
= 3(14)
= 42
q = n + 4
= (14) + 4
= 18
It is 900,000 it is in the hundreds thousandths place.
Answer:
9.
h(x)=-x-1
let y =-x-1
interchanging role of x & y
x=-y-1
y=-x-1
h-¹(x)=-x-1
again
f(x)=(2-3x)/2
let
y=(2-3x)/2
interchanging role of x & y
x=(2-3y)/2
2x-2=-3y
y=(2-2x)/3
f-¹(x)=(2-2x)/3
<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>f</u><u>u</u><u>n</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>n</u><u>o</u><u>t</u><u> </u><u>i</u><u>n</u><u>v</u><u>e</u><u>r</u><u>s</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>o</u><u>t</u><u>h</u><u>e</u><u>r</u><u>.</u>
10.
f(x)=-x+3
let y=-x+3
interchanging role of x & y
x=-y+3
y=3-x
f-¹(x)=-x+3
equal to g(x)=-x+3
<u>Given function are</u><u> inverse of each other.</u>
Answer:
500 2000
Step-by-step explanation: