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Effectus [21]
2 years ago
13

ILL GIVE BRAINLYyYYYyYYyyyyy

Physics
1 answer:
pshichka [43]2 years ago
8 0

Answer:

<u>The</u><u> </u><u>best</u><u> </u><u>thermal</u><u> </u><u>insulators</u><u> </u><u>have</u><u> </u><u>free</u><u> </u><u>electrons</u>

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Please need help on this thank you
lys-0071 [83]
I am pretty sure it is B....
6 0
2 years ago
Astronauts are trained for take-off in a high-speed centrifuge of 4.7 m radius that spins in the horizontal plane.
Leokris [45]

Answer:

a) 1.94 \frac{rad}{s}

b) 9.12\frac{m}{s}

c) Towards the center of the centrifuge

Explanation:

a)

Becuse the centrifuge rotates in circular motion, there's an angular acceleration tha simulates high gravity accelerations

a_{rad}=\omega r^{2}

with r the radius and ω the amgular velocity, in or case a_rad=3.5g so:

3.5g=\omega r^{2} and g=9.8\frac{m}{s^{2}}

solving for ω:

\omega=\frac{3.5g}{r^2}=\frac{3.5*9.8}{4.2^2}

\omega = 1.94 \frac{rad}{s}

b) Linear speed (v) and angular speed are related by:

v=\omega r =(1.94)(4.7)

v= 9.12\frac{m}{s}

c) The apparent weigth is pointing towards the center of the circle, becuse angular acceleration is pointing in that direction.

8 0
2 years ago
A 50-kg copper block initially at 140°c is dropped into an insulated tank that contains 90 l of water at 10°c. Determine the f
xxMikexx [17]

Answer:

T_f=24.71

Explanation:

From the question we are told that:

Mass of block m=50

Temperature of block T_b =140 \textdegree C

Volume of water V= 90L

Temperature of water T_w=10 \textdegree C

Density of water \rho=1000kg/m^3

Specific heat of water C_w=4.18KJ/kg-k

Specific heat of copper C_p=0.96KJ/kg-k

 

Generally the equation for equilibrium stage is mathematically given by

mC_p(T_b-T_f)=\rho*VV*c(T_f-T_w)

50*0.96(140-T_f)=1000*90*10^-3*c_w(T_f-10)

48(140-T_f)=376.2(T_f-10)

140-T_f=7.8375(T_f-10)

140-T_f=7.8375T_f-78.375

-8.8375T_f=-218.375

T_f=\frac{-218.375}{-8.8375}

T_f=\frac{-218.375}{-8.8375}

T_f=24.71

6 0
2 years ago
If you are
zysi [14]

Answer:

yes it doesn't matter

Explanation:

it doesn't matter because troughs and crests are the same and either can be used

7 0
1 year ago
Explain how the basic unit are combined to give the derived units of force, velocity, pressure and work
LuckyWell [14K]

Velocity:

Velocity is change in displacement with respect to time:

\frac{\Delta x}{\Delta t}

Analysing the units, meters (displacement) and seconds (time) are basic units:

\frac{m}{s}

Therefore the unit of velocity is m/s

Force:

Newton's second law of motion:

F = ma

Kilogram (mass) is a basic unit, and accelerations unit can be found using the equation:

a=\frac{\Delta v}{\Delta t}

Analysing the units:

\frac{\frac{m}{s}}{s}=\frac{m}{s^2}

Therefore, the unit of force is:

kg\frac{m}{s^2}

Pressure:

Pressure is given by the equation:

P=\frac{F}{S} where S is area of effect, F is force

Area for a basic rectangle (geometric shape is arbitrary for dimensional analysis) is found by multiplying two lengths:

[l^2]=m^2, the unit of area

Dividing the aforementioned unit of force by the unit of area:

\frac{kg\frac{m}{s^2}}{m^2}=\frac{kg}{ms^2}, the unit of pressure

Work:

Work is given by the equation:

W=\vec{F}\cdot \vec{x}, (dot product may be assumed as normal multiplication for the purposes of unit analysis)

Knowing displacement's (x) unit is m:

[W]=\frac{kgm}{s^2}m=\frac{kgm^2}{s^2}, the unit of work.

3 0
2 years ago
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