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Tpy6a [65]
3 years ago
9

Write the pressure equilibrium constant expression for this reaction. 2CO2 (g) + 4H2O (g) → 2CH3OH (l) + 3O2 (g)

Chemistry
1 answer:
-BARSIC- [3]3 years ago
3 0

Answer:

The pressure equilibrium constant (Kp) = (P O₂)³/(P CO₂)²(P H₂O)⁴.

Explanation:

  • For the reaction:

<em>2CO₂ (g) + 4H₂O (g) → 2CH₃OH (l) + 3O₂ (g).</em>

<em></em>

The pressure equilibrium constant (Kp) = the product of the pressure of the products side components / the product of the pressure of the reactantss side components.

each one is raised to a power equal to its coefficient.

<em>∴ The pressure equilibrium constant (Kp) = (P O₂)³/(P CO₂)²(P H₂O)⁴.</em>

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2 years ago
Which statements describe codominance? Select three options.
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4 0
3 years ago
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Consider the following data. NO2(g) equilibrium reaction arrow identifying the requirement for light NO(g) + O(g) K = 6.8 ✕ 10-4
LenKa [72]

Answer:

K=3.9*10^{-82}

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To achive the reaction we combine those two reactions:

NO_2 (g) + O_3 (g) + NO (g) \longleftrightarrow NO (g) + O (g) + NO_2 (g)

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4 0
3 years ago
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Answer:

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5 0
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