A vertical plate has a sharp-edged orifice at its center. A water jet of speed V strikes the plate concentrically. Obtain an exp
ression for the external force needed to hold the plate in place, if the jet leaving the orifice also has speed V. Evaluate the force for V515 ft/s, D54 in., and d51 in. Plot the required force as a function of diameter ratio for a suitable range of diameter d.
1 answer:
Answer:
Force = 455672061 N
Explanation:
given data
V = 515 ft/s
D = 54 in = 4.5 ft
d = 51 in = 4.25 ft
to find out
Evaluate the force
solution
we know that force is express as
force F = ρ ΔA v² ..................1
put here value we get
force F = 1000 × [ D² - d² ] × v²
F = 1000 × [ 4.5² - 4.25² ] × 515²
Force = 455672061 N
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Answer:
Explanation:
Height h = 1.03m
Volume v = 3780 gallons = 3780 * 0.0037851m^3 = 14.3073m^3
Time t = 13.5 mins = 13.5 * 60 = 810 seconds
Length of pool L = 14 inch = 14 * 2.54 = 35.56cm
width of pool b = 48 inch = 48 * 2.54 = 121.92 cm
a.) Consider the bernoulli's equation is given as:
consider the equation of bernoulli at the top of the pool
where atm pressure
At the top of the pool , substitute in V_1 in equation (2)
Hence equation (3) serves as the bernoullis equation at the top.
b.) Consider the equation of bernoulli's at the opening of the pool
where atm pressure and
Hence equation (6) serves as the bernoullis equation of water at the opening of the pool.
c.) Consider the equation (3) and (4)
Hence velocity is
d.) consider (7)
This is the norminal value of velocity
e.) consider the equation of flow rate interval of v and t
flow(t)= hence this is the flow rate
f.) Consider the equation cross sectional area in terms of V,v2 and t
hence this serves as the cross sectional area.
g.) Consider the equation of area from equation (8)
Answer:
F₁ = 1500 N
F₂ = 750 N
= 500 N
Explanation:
Given :
Power transmission, P = 7.5 kW
= 7.5 x 1000 W
= 7500 W
Belt velocity, V = 10 m/s
F₁ = 2 F₂
Now we know from power transmission equation
P = ( F₁ - F₂ ) x V
7500 = ( F₁ - F₂ ) x 10
750 = F₁ - F₂
750 = 2 F₂ - F₂ ( ∵F₁ = 2 F₂ )
∴F₂ = 750 N
Now F₁ = 2 F₂
F₁ = 2 x F₂
F₁ = 2 x 750
F₁ = 1500 N , this is the maximum force.
Therefore we know,
= 3 x
where is centrifugal force
=
/ 3
= 1500 / 3
= 500 N
Answer:
1028.1184 Ohms
Explanation:
<u>Given the following data;</u>
- Initial resistance, Ro = 976 Ohms
- Initial temperature, T1 = 0°C
- Final temperature, T2 = 89°C
Assuming the temperature coefficient of resistance for carbon at 0°C is equal to 0.0006 per degree Celsius.
To find determine its new resistance, we would use the mathematical expression for linear resistivity;
Substituting into the equation, we have;