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Makovka662 [10]
4 years ago
6

A vertical plate has a sharp-edged orifice at its center. A water jet of speed V strikes the plate concentrically. Obtain an exp

ression for the external force needed to hold the plate in place, if the jet leaving the orifice also has speed V. Evaluate the force for V515 ft/s, D54 in., and d51 in. Plot the required force as a function of diameter ratio for a suitable range of diameter d.

Engineering
1 answer:
Vesnalui [34]4 years ago
8 0

Answer:

Force = 455672061 N

Explanation:

given data

V = 515 ft/s

D = 54 in = 4.5 ft

d = 51 in = 4.25 ft

to find out

Evaluate the force

solution

we know that force is express as

force F = ρ ΔA v²     ..................1

put here value we get

force F = 1000 × \frac{\pi}{4} [ D² - d² ] × v²

F = 1000 × \frac{\pi}{4} [ 4.5² - 4.25² ] × 515²

Force = 455672061 N

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C. assembly line workers.

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Technician A says inspecting the operation of the automatic emergency brake system helps determine whether the spring brakes wil
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When testing a spring break it is advisable to Step on and off the brake, with the engine off, the parking brake knob is expected to pop out when air pressure falls between 20-40 psi.

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Practice Problem: Large-Particle CompositesThe mechanical properties of a metal may be improved by incorporating fine particles
trasher [3.6K]

Answer: (a). Ec(μ) = 165.6 GPa

(b). Ec(∝) = 83.09 GPa

Explanation:

this is quite straightforward, so we will go step by step.

from the data we have that,

Moduli of elasticity of the metal  -(Em) is 60 Gpa

Moduli of elasticity of oxide is  (Ep) is 380 Gpa

volume Vp = 33% = 0.33

(a). To solve the upper bound-modulus of the elasticity is calculate thus;

Ec (μ) = EmVm + EpVp ----------------(1)

where E rep the modulus of elasticity

v rep the volume fraction

c rep the composite

Vm = 100% - Vp

Vm =  100% - 33% = 67%

Vm = 0.67

substituting the valus of Em, Vm, Ep, Vp  from equation (1) we have;

Ec(μ) = (60×0.67) + (380×0.33)

Ec(μ) = 40.2 + 125.4 = 165.6 GPa

Ec(μ) = 165.6 GPa

(b). The lower bound modulus of elasticity can be calculated thus;

Ec(∝) = EmVp / EpVm + EmVp -------------- (2)

substituting values Em,Vm,Ep,Vp.

Ec(∝) = 60×30 / (380×0.67) + (60 ×0.33)

Ec(∝) = 22800 / 254.6 + 19.8 = 83.09 GPa

Ec(∝) = 83.09 GPa

cheers i hope this helps!!!!

6 0
4 years ago
A closed, rigid, 0.45 m^3 tank is filled with 12 kg of water. The initial pressure is p1 = 20 bar. The water is cooled until the
liberstina [14]

Answer:

initial quality = 0.3690

heat transfer = 979.63 kJ/kg

Explanation:

Given data:

volume of tank 0.45^3

weight of water 12 kg

Initial pressure 20 bar

final pressure 4 bar

Specific volume v = \frac {0.45}{12} = 0.0375 m^3/kg

At Pressure = 20 bar, from saturated water table

v_f = 0.01177 m^/kg

v_g = 0.099587 m^3/kg

x = \frac{v -v_f}{v_g -v_f} = \frac{0.0375 - 0.001177}{0.099587 - 0.001177}

inital quality is x =0.3690

Heat transfer is calculated as

u_1 = h_f + x(h_g - h_f) = v_f + x( h_{fg})

from saturated water table, for pressure 20 bar ,

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     =908.79 + 0.0357(1890.7)

      = 979.63 kJ/kg

7 0
3 years ago
pump delivers 11000 lb/hr of water from an elevation 30 ft below the pump to an elevation 50 ft above the pump through various d
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Answer:

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Explanation:

4 0
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