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IceJOKER [234]
4 years ago
14

How is light being described?

Physics
1 answer:
Slav-nsk [51]4 years ago
7 0
Light is described as both wave as well particle because light behave as wave in phenomenon like diffraction, interference, refraction, Doppler effect, etc whereas it behave as a particle in phenomenon like photoelectric effect, etc. Hope this helps.
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A mass weighing 4 pounds is attached to a spring whose constant is 2 lb/ft. The medium offers a damping force that numerically e
Neko [114]

Answer:

the time at which it passes through the equilibrum position is:

t = 0.1 second

Explanation:

given

w= 4pounds

k(spring constant) = 2lb/ft

g(gravitational constant) = 10m/s² = 32ft/s²

β(initial point above equilibrum) = 1

velocity = 14ft/s

attached is an image showing the calculations, because some of the parameters aren't convenient to type.

3 0
3 years ago
The city of Istanbul turkey sits on what?
Sati [7]

Istanbul is a transcontinental city in Eurasia, straddling the Bosporus strait (which separates Europe and Asia) between the Sea of Marmara and the Black Sea. Its commercial and historical center lies on the European side and about a third of its population lives in suburbs on the Asian side of the Bosporus.

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4 years ago
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3 0
3 years ago
The speed of light in cubic zirconia
schepotkina [342]

The index of refraction for the cubic zirconia at the given speed of light is 2.16.

The given parameters:

  • <em>Speed of light in Cubic zirconia, v = 1.39 x 10⁸ m/s</em>
  • <em>Speed of light in air, c = 3.0 x 10⁸ m/s.</em>

The index of refraction for the cubic zirconia is the ratio of the speed of light in air to speed of light in cubic zirconia and it is calculated as follows;

\eta = \frac{c}{v} \\\\\eta = \frac{3\times 10^8}{1.39 \times 10^8} \\\\\eta = 2.16

Thus, the index of refraction for the cubic zirconia at the given speed of light is 2.16.

Learn more about index of refraction here: brainly.com/question/10729741

6 0
3 years ago
If the mass of an object increases, how is its acceleration affected, assuming the net force acting on the object remains the sa
vovikov84 [41]
Based on Newton's second law of motion, the net force applied to an object is equal to the product of the mass of the object and the acceleration it experiences. That is,
  
          F = ma

If we are to assume that the net force is constant and that the mass is increased, the acceleration should therefore decrease in order to make constant the value at the right-hand side of the equation. 
7 0
3 years ago
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