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Alekssandra [29.7K]
3 years ago
8

Explain the importance of water quality in aquaculture business.

Engineering
2 answers:
mars1129 [50]3 years ago
5 0

Answer:

Mantain the image of the business

Explanation:

Good water quality gives good images to others and furthers business

Scorpion4ik [409]3 years ago
4 0

Answer:

this is very important the agricultural because there can be a risk of hight salt concentrations that can limit the amount of water plants can take

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A pipe leads from a storage tank on the roof of a building to the ground floor. The absolute pressure of the water in the storag
Fudgin [204]

Answer:

6.4 m/s

Explanation:

From the equation of continuity

A1V1=A2V2 where A1 and V1 are area and velocity of inlet respectively while A2 and V2 are the area and velocity of outlet respectively

A1=\pi (r1)^{2}

A2=\pi (r2)^{2}

where r1 and r2 are radius of inlet and outlet respectively

v1 is given as 1.6 m/s

Therefore

\pi (0.01)^{2}\times 1.6 = \pi (0.005)^{2}v2

V2=\frac {\pi (0.01)^{2}\times 1.6}{\pi (0.005)^{2}}=6.4 m/s

3 0
4 years ago
a valueable preserved biological specimen is weighed by suspeding it from a spring scale. it weighs 0.45 N when it is suspendedi
Dmitry_Shevchenko [17]

Answer:

ρ=962.16kg/m^3

Explanation:

The first thing we must do to solve is to find the mass of the specimen using the weight equation

w = mg

m=w/g

m=0.45/9.81=0.04587kg

To find the volume we must make a free-body diagram on the specimen, taking into account that the weight will go down and the buoyant force up, and the result of that subtraction will be the measured weight value (0.081N).

We must bear in mind that the principle of archimedes indicates that the buoyant force is given by

F = ρgV

where V is the specimen volume and  ρ is the density of alcohol = 789kg / m ^ 3

considering the above we have the following equation

0.081=0.45-(789)(9.81m/s^2)V

solving for V

V=(0.081-0.45)/(-789x9.81)

V=4.7673x10^-5m^3

finally we found the density

ρ=m/v

ρ=0.04587kg/4.7673x10^-5m^3

ρ=962.16kg/m^3

4 0
4 years ago
Please dimension this, was due yesterday.
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Love the image isn’t showing up. Try reposting it!
6 0
3 years ago
Write a program that randomly chooses between three different colors for displaying text on the screen. Use a loop to display tw
11Alexandr11 [23.1K]

Answer:

INCLUDE Irvine32.inc

.data

msgIntro  byte "This is Your Name's fourth assembly extra credit program. Will randomly",0dh,0ah

         byte "choose between three different colors for displaying twenty lines of text,",0dh,0ah

         byte "each with a randomly chosen color. The color probabilities are as follows:",0dh,0ah

         byte "White=30%,Blue=10%,Green=60%.",0dh,0ah,0

msgOutput byte "Text printed with one of 3 randomly chosen colors",0

.code

main PROC

;

//Intro Message

       mov edx,OFFSET msgIntro  ;intro message into edx

       call WriteString         ;display msgIntro

       call Crlf                ;endl

       call WaitMsg             ;pause message

       call Clrscr              ;clear screen

       call Randomize           ;seed the random number generator

       mov edx, OFFSET msgOutput;line of text

       mov ecx, 20              ;counter (lines of text)

       L1:;//(Loop - Display Text 20 Times)

       call setRanColor         ;calls random color procedure

       call SetTextColor        ;calls the SetTextColor from library

       call WriteString         ;display line of text

       call Crlf                ;endl

       loop L1

exit

main ENDP

;--

setRanColor PROC

;

; Selects a color with the following probabilities:

; White = 30%, Blue = 10%, Green = 60%.

; Receives: nothing

; Returns: EAX = color chosen

;--

       mov eax, 10              ;range of random numbers (0-9)

       call RandomRange         ;EAX = Random Number

       .IF eax >= 4          ;if number is 4-9 (60%)

       mov eax, green           ;set text green

       .ELSEIF eax == 3         ;if number is 3 (10%)

       mov eax, blue            ;set text blue

       .ELSE                    ;number is 0-2 (30%)

       mov eax, white           ;set text white

       .ENDIF                   ;end statement

       ret

setRanColor ENDP

6 0
3 years ago
You are an engineer in an electric-generation station. You know that the flames in the boiler reach a temperature of 1200 K and
olga nikolaevna [1]

Answer:

<em>The maximum efficiency the plant will ever achieve is 75%</em>

<em>Explanation:</em>

From the question given, we recall the following:

<em>Th flames in the boiler reaches a temperature of = 1200K</em>

<em>the cooling water is = 300K</em>

<em>The maximum efficiency the plant will achieve is defined as:</em>

Let nmax = 1 - Tmin /Tmax

Where,

Tmin = Minimum Temperature in plants

Tmax = Maximum Temperature in plants

The temperature of the cooling water  = Tmin = 300K

The temperature of the flames in boiler = Tmax = 1200k=K

The maximum efficiency becomes:

nmax =  1 - Tmin /Tmax

nmax =  1 - 300 /1200

nmax =  1-1/4 =0.75

nmax =  75%

5 0
4 years ago
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