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4 years ago

When copper combines with oxygen to form copper oxide, the charge of the copper ion is

Physics

2 answers:

Archy [21]4 years ago

8 0

The copper and oxygen and oxygen atoms are not ions, and the bonds are more covalent than they are ionic.

saveliy_v [14]4 years ago

4 0

Cu(s)+O2(g)-->CuO
The copper ion will technically have a +2 charge

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The radius of he Earth orbit around the sun (assumed circular) is 1.50 X 10^8km, with T=365d. What is the radial acceleration of

Karolina [17]

Answer:

ar = 5.86*10^-3 m/s^2

Explanation:

In order to calculate the radial acceleration of the Earth, you first take into account the linear speed of the Earth in its orbit.

You use the following formula:

$v=\sqrt{\frac{GM_s}{r}}$ (1)

G: Cavendish's constant = 6.67*10^-11 m^3 kg^-1 s^-2

Ms: Sun's mass = 1.98*10^30 kg

r: distance between Sun ad Earth = 1.50*10^8 km = 1.50*10^11 m

Furthermore, you take into account that the radial acceleration is given by:

$a_r=\frac{v^2}{r}$ (2)

You replace the equation (1) into the equation (2) and replace the values of all parameters:

$a_r=\frac{1}{r}\frac{GM_s}{r}=\frac{GM_s}{r^2}\\\\a_r=\frac{(6.67*10^{-11}m^3kg^{-1}s^{-2})(1.98*10^{30}kg)}{(1.50*10^{11}m)^2}\\\\a_r=5.86*10^{-3}\frac{m}{s^2}$

The radial acceleration of the Earth, towards the sun is 5.86*10^-3 m/s^2

7 0

3 years ago

What is the speed between reflected ray and the incident ray

Korvikt [17]

Answer:

The speed is the same as long as the reflection is regular.

Explanation:

This is because in regular reflection, the angle of incidence is equal to the angle of reflection in accordance with the second law of reflection.

Since speed of light depends on the angle of the light ray it makes with the reflecting surface, the speed is the same

7 0

4 years ago

A boat is travelling due west at a speed of 47 miles per hour. If the boat started off 170 miles directly north of the city of S

ankoles [38]

Answer is miles sir your welcome it was simple

6 0

3 years ago

Which is not a characteristic of an ideal fluid?

Lena [83]

The answer would be B

7 0

3 years ago

Three moles of an ideal gas are taken around the eyele acb shown in Fig.For this gas Co-29.2J/mol-K.Process ac is at constant pr

Scorpion4ik [409]

For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as

Wt=1945.475J

<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>

Generally, the equation for work is mathematically given as

Wt=wac+Wc+Wba

Therefore

Wac=Pa(Vc-Va)=nR(Tc-Ta)

Wac=3(8.314*192)

Wac=4788.864J

Wcb=P1v1-p2v2/v-1

Wcb-3*8.34*108/0.4

Wcb=-6734.34J

Wab=0

In conclusion,

Wt=wac+Wc+Wba

Wt=4788.864J+0+(-6734.34J)

Wt=+1945.475J