12.5 mL of NaOH solution
Explanation:
We have the following chemical reaction in which sodium hydroxide (NaOH) react with acetic acid (CH₃-COOH) to form sodium acetate (CH₃-COONa) and water (H₂O):
NaOH + CH₃-COOH → CH₃-COONa + H₂O
molar concentration = number of moles / volume
number of moles = molar concentration × volume
number of moles of CH₃-COOH = 0.2 × 12.5 = 2.5 mmoles
*typically a vinegar solution have a concentration of acetic acid of 12.5 mol/L.
Taking in account the chemical reaction, we devise the following reasoning:
if 1 mmole of NaOH reacts with 1 mmole of CH₃-COOH
then X = 2.5 mmoles of NaOH reacts with 2.5 mmoles of CH₃-COOH
volume = number of moles / molar concentration
volume of NaOH solution = 2.5 / 0.2 = 12.5 mL
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Percent by mass of an element can be calculated as
(Total mass of the element in the formula / formula weight ) * 100
Step 1 : Find formula weight of NaHCO₃
To find formula weight of NaHCO₃, we have to add atomic masses of the elements Na, H,C and O
Formula weight of NaHCO₃ = 
Formula weight of NaHCO₃ = 
Formula weight of NaHCO₃ is 84.01 g
Step 2 : Use percent by mass formula
Percent by mass of oxygen = (total mass of oxygen / formula weight) * 100
Percent by mass of oxygen = 
Percent by mass of oxygen = 57.14%
Answer : percentage by mass of oxygen in a formula unit of sodium hydrogen carbonate (NaHCO3) is 57.14%