1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PIT_PIT [208]
3 years ago
12

On the sunlit surface of Venus, the atmospheric pressure is 9.0 106 Pa, and the temperature is 740 K. On the earth's surface the

atmospheric pressure is 1.0 105 Pa, while the surface temperature can reach 320 K. These data imply that Venus has a "thicker" atmosphere at its surface than does the earth, which means that the number of molecules per unit volume (N/V) is greater on the surface of Venus than on the earth. Find the ratio (N/V)Venus / (N/V)Earth.

Physics
2 answers:
uranmaximum [27]3 years ago
4 0

Answer:

(1) Venus    $\frac{n}{v} = 1.464494797*10^-3$

(2) Earth $\frac{n}{v} = 3.797975698*10^-4

Explanation:

Ideal Gas Equation which relates these quantities of thermodynamics is.

PV=NRT  where P is pressure, V is volume , N is number of molecules, R is ideal Gas Constant and has value of 8.3144621J/Mol*K.

Rearranging the above equation, by first solving for N in terms of P, V, R and T and then dividing by V gives us.

\frac{N}{V} =\frac{P}{RT}

Now it is only matter of Plugging in numbers so for Venus planet we can plug in P = 9.0106Pa, T = 740K R is constant in every situation = 8.3144621J/mol K. and get (1) and similarly for Earth we will plug in P = 1.0105Pa , T = 320K and same R, and will get (2).

iren2701 [21]3 years ago
3 0

Answer:

the ratio (N/V)Venus / (N/V)Earth = 39 : 1

Explanation:

Detailed explanation and calculation is shown in the image below

You might be interested in
A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?
pychu [463]

Answer:

how can we get the best out with a little of my life and I think the most common reason I would n I have been having this problem for years is done in my life as the other people

6 0
2 years ago
A diver stands on a diving platform 10.0 m above the surface of a pool and leaps upward with an initial speed of 2.5 m/s. how fa
Alexus [3.1K]
<span>The diver is heading downwards at 12 m/s Ignoring air resistance, the formula for the distance under constant acceleration is d = VT - 0.5AT^2 where V = initial velocity T = time A = acceleration (9.8 m/s^2 on Earth) In this problem, the initial velocity is 2.5 m/s and the target distance will be -7.0 m (3.0 m - 10.0 m = -7.0 m) So let's substitute the known values and solve for T d = VT - 0.5AT^2 -7 = 2.5T - 0.5*9.8T^2 -7 = 2.5T - 4.9T^2 0 = 2.5T - 4.9T^2 + 7 We now have a quadratic equation with A=-4.9, B=2.5, C=7. Using the quadratic formula, find the roots, which are -0.96705 and 1.477251164. Now the diver's velocity will be the initial velocity minus the acceleration due to gravity over the time. So V = 2.5 m/s - 9.8 m/s^2 * 1.477251164 s V = 2.5 m/s - 14.47706141 m/s V = -11.97706141 m/s So the diver is going down at a velocity of 11.98 m/s Now the negative root of -0.967047083 is how much earlier the diver would have had to jump at the location of the diving board. And for grins, let's compute how fast he would have had to jump to end up at the same point. V = 2.5 m/s - 9.8 m/s^2 * (-0.967047083 s) V = 2.5 m/s - (-9.477061409 m/s) V = 2.5 m/s + 9.477061409 m/s V = 11.97706141 m/s And you get the exact same velocity, except it's the opposite sign. In any case, the result needs to be rounded to 2 significant figures which is -12 m/s</span>
7 0
3 years ago
The corona
balu736 [363]

Answer:

B

Explanation:

7 0
2 years ago
Read 2 more answers
Protons in an atomic nucleus are typically 10−15 m apart. what is the electric force (in n) of repulsion between nuclear protons
dybincka [34]
<span>The electric force is given by: 
 F = [ k*(q1)*(q2) ] / d^2 
 F = Electric force 
 k = Coulomb's constant 
 q1 = Charge of one proton 
 q2 = Charge of second proton 
 d = Distance between centers of mass 
 Values: 
 F = unknown 
 k = 8.98E 9 N-m^2/C^2 
 q1 = 1.6E-19 
 q2 = 1.6E-19 
 d = 1.0E-15 m 
 Insert values into F = [ k*(q1)*(q2) ] / d^2 
 F = [ (8.98E 9 N-m^2/C^2) * (1.6E-19) * (1.6E-19) ] / (1.0E-15 m)^2 
 F = </span>229.888 N
 answer
 the electric force of repulsion between nuclear protons is 229.888 N

3 0
3 years ago
Read 2 more answers
A rare and valuable antique chest is being moved into a truck using a 4.00 m long ramp. the kj weight of the chest plus packing
Lisa [10]

First let us calculate for the angle of inclination using the sin function,

sin θ = 1 m / 4 m

θ = 14.48°

 

Then we calculate the work done by the movers using the formula:

W = Fnet * d

 

So we must calculate for the value of Fnet first. Fnet is force due to weight minus the frictional force.

Fnet = m g sinθ – μ m g cosθ

Fnet = 1,500 sin14.48 – 0.2 * 1,500 * cos14.48

Fnet = 84.526 N

 

So the work exerted is equal to:

W = 84.526 N * 4 m

<span>W = 338.10 J</span>

7 0
3 years ago
Other questions:
  • Kristen is running a half marathon. By her tenth minute of running, her breathing rate has increased from her resting rate.
    8·2 answers
  • If a forces of 40 newtons moves a cart a distance of 9 meters, the work done is?
    5·1 answer
  • 5. A massless string passes over a frictionless pulley and carries
    11·1 answer
  • A circular loop of wire is positioned so the normal to its area points vertically upward. A bar magnet is dropped from above the
    14·1 answer
  • How do I solve for time if I have initial velocity and final speed?
    7·1 answer
  • A student who takes a multiple-choice test by reading the stem of each item, generating the correct response before looking at t
    15·1 answer
  • Question number 7, how to calculate the equivalent resistance of the combination of resistors.
    8·1 answer
  • Streams have a detectable current, while rivers do not.
    15·1 answer
  • An object's mass refers to _____ and an object's weight refers to _____. Fill in each blank.
    13·1 answer
  • Describe what the sun would look like from earth if the entire photosphere were the same temperature as a sunspot?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!