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PIT_PIT [208]
3 years ago
12

On the sunlit surface of Venus, the atmospheric pressure is 9.0 106 Pa, and the temperature is 740 K. On the earth's surface the

atmospheric pressure is 1.0 105 Pa, while the surface temperature can reach 320 K. These data imply that Venus has a "thicker" atmosphere at its surface than does the earth, which means that the number of molecules per unit volume (N/V) is greater on the surface of Venus than on the earth. Find the ratio (N/V)Venus / (N/V)Earth.

Physics
2 answers:
uranmaximum [27]3 years ago
4 0

Answer:

(1) Venus    $\frac{n}{v} = 1.464494797*10^-3$

(2) Earth $\frac{n}{v} = 3.797975698*10^-4

Explanation:

Ideal Gas Equation which relates these quantities of thermodynamics is.

PV=NRT  where P is pressure, V is volume , N is number of molecules, R is ideal Gas Constant and has value of 8.3144621J/Mol*K.

Rearranging the above equation, by first solving for N in terms of P, V, R and T and then dividing by V gives us.

\frac{N}{V} =\frac{P}{RT}

Now it is only matter of Plugging in numbers so for Venus planet we can plug in P = 9.0106Pa, T = 740K R is constant in every situation = 8.3144621J/mol K. and get (1) and similarly for Earth we will plug in P = 1.0105Pa , T = 320K and same R, and will get (2).

iren2701 [21]3 years ago
3 0

Answer:

the ratio (N/V)Venus / (N/V)Earth = 39 : 1

Explanation:

Detailed explanation and calculation is shown in the image below

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Ksivusya [100]

Answer:

The answer is 1.87nm/s.

Explanation:

The 110g/hr  water loss must be replaced by 110g/hr of sap. 110g of sap corresponds to a volume of  

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thus rate of sap replacement is

106cm^3/hr = 106*10^{-6}m^3/3600s  = 2.94*10^{-8}m^3/s

The volume of sap in the vessel of length x is

V = Ax,

where A is the cross sectional area of the vessel.

For 2000 such vessels, the volume is

V = 2000Ax

taking the derivative of both sides we get:

\dfrac{dV}{dt} = 2000A \dfrac{dx}{dt}

on the left-hand-side \dfrac{dx}{dt} is the velocity v of the sap, and on right-hand-side \dfrac{dV}{dt}  = 2.94*10^{-8}m^3/s; therefore,

2.94*10^{-8}m^3/s=2000Av

and since the cross-sectional area is

A = \pi (\dfrac{100*10^{-3}m}{2} )^2 = 7.85*10^{-3}m^2;

therefore,

2.94*10^{-8}m^3/s =2000(7.85*10^{-3}m^2)v

solving for v we get:

v = \dfrac{2.94*10^{-8}m^3/s}{2000(7.85*10^{-3}m^2)}

\boxed{v =1.875*10^{-9}m/s = 1.875nm/s}

which is the upward speed of the sap in each vessel.

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3 years ago
The sun _____.
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The sun <u><em>appears</em></u> brighter than any other star.

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for example: water when heated it undergoes a Physical Change and turn into vapor, this means the heat cause the distance between water molecules to increase, so it transferred from the liquid form to the gas form. 

NOTE that in Physical Change there is no change in the chemical structure and the material retains all its chemical properties, and no new compounds are produced. 

again, A physical change is any change not involving a change in the substance's chemical identity. Matter undergoes chemical change when the composition of the substances changes: one or more substances combine or break up (as in a relationship) to form new substances.Physical changes occur when objects undergo a change that does not change their chemical nature. A physical change involves a change in physical properties. Physical properties can be observed without changing the type of matter. Examples of physical properties include: texture, shape, size, color, odor, volume, mass, weight, and density. 

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5 0
3 years ago
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What is the maximum number of primary partitions that gpt supports?
Vikki [24]
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4 0
3 years ago
An electron enters the gap between the plates of a capacitor at the center of the gap traveling parallel to theplates at 2.0 x 1
Svetlanka [38]

Answer:

How far will the electron travel beforehitting a plate is 248.125mm

Explanation:

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Where charge density=1.0 x 10^-6C/m2 & epsilon nought= 8.85× 10^-12

Therefore E = 1.0 x 10^-6/8.85× 10^-12

E= 1.13×10^5N/C

Force on electron F=qE

Where q=charge of electron=1.6×10^-19C

Therefore F=1.6×10^-19×1.13×10^5

F=1.808×10^-14N

Acceleration on electron a = Force/Mass

Where Mass of electron = 9.10938356 × 10^-31

Therefore a= 1.808×10^-14 /9.11 × 10-31

a= 1.985×10^16m/s^2

Time spent between plate = Distance/Speed

From the question: Distance=1cm=0.01m and speed = 2×10^6m/s^2

Therefore Time = 0.01/2×10^6

Time =5×10^-9s

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S= 1.985×10^16×(5×10^-9)^2/2

S=24.8125×10^-2m

S=248.125mm

4 0
3 years ago
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