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3 years ago

How to determine if the ionic bond between lithium fluoride is stronger or weaker than the ionic bond in magnesium oxide?

Chemistry

1 answer:

lara [203]3 years ago

4 0

Explanation:

As we know that the atomic number of lithium is 3 and its electronic distribution is 2, 1. Whereas atomic number of fluorine is 9 and its electronic distribution is 2, 7. So, for a metal it is easier to lose an electron rather than losing 2 or more number of electrons.

Also, fluorine is much more electronegative in nature. Hence, it will readily accept an electron from a donor atom. Therefore, a strong ionic bond will be present between lithium and fluorine atom.

On the other hand, atomic number of magnesium is 12 and its electronic configuration is 2, 8, 2. And, atomic number of oxygen is 8 and its electronic distribution is 2, 6. Also, oxygen is less electronegative than fluorine therefore, force of attraction exerted by oxygen to gain the valence electrons will not be strong enough.

Hence, the ionic bond between magnesium oxide is not strong enough.

Thus, we can conclude that ionic bond between lithium fluoride is stronger than ionic bond in magnesium oxide.

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Answer:

Diamagnetism in atom occurs whenever two electrons in an orbital paired equalises with a total spin of 0.

Paramagnetism in atom occurs whenever at least one orbital of an atom has a net spin of electron. That is a paramagnetic electron is just an unpaired electron in the atom.

Here is a twist even if an atom have ten diamagnetic electrons, the presence of at least one paramagnetic electron, makes it to be considered as a paramagnetic atom.

Simply put paramagnetic elements are one that have unpaired electrons, whereas diamagnetic elements do have paired electron.

The atomic orbital and radius increases by gaining electron linearly so even electron numbered atoms are diamagnetic while the odd electron numbered atoms are paramagnetic.

Running through the first 18 elements one can observe that there is an alternative odd number of electrons and an even number proofing that that half of the first 18 elements shows paramagnetism and diamagnetism respectively.

Explanation:

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3 years ago

A dull metal object has a density of 8.8 G/ML and a volume of 20 ML calculate the mass

Alex

Answer:

Mass = 0.000176 gram

Steps:

m = V × ρ

= 20 milliliter × 8.8 gram/cubic meter

= 2.0E-5 cubic meter × 8.8 gram/cubic meter

= 0.000176 gram

Explanation:

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3 years ago

What are the uses of solution?<br>

Ilia_Sergeevich [38]

Answer:

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Turpentine as a solvent are used in the production of paints, inks and dyes. ↔Water as a solvent is used in the making of food, textiles, soaps and detergents. ↔Alloys are solid solutions that are used in the manufacture of cars, aerospace and other vehicles.

Explanation:

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