Answer: 130°C
Explanation:
1) Data:
i) material: lead
ii) m = 57 g
iii) Q = 146 cal
iv) Ti = 47°C
v) Tf = ?
2) Formulas
Q = m C (Tf - Ti)
C is the specific heat of lead. You must find that value in tables using your textbook or researching in internet.
Such value is C = 0.031 cal / g°C
3) Solution
Q = m C (Tf - Ti) ⇒ Tf - Ti = Q / m C ⇒ Tf = Ti + Q /m C
⇒Tf = 47°C + 146 cal / (57g × 0.031 cal / g°C) = 47°C + 82.6°C = 129.6°C ≈ 130°C
We have that The acceleration due to gravity on the Moon And
The acceleration due to gravity on the surface of the Earth is approximately
From the Question we are asked
The value of G on earth and moon?
Where G refers to The acceleration due to gravity
Generally
The acceleration due to gravity on the Moon is approximately
And
The acceleration due to gravity on the surface of the Moon is approximately
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Answer:21
Explanation:every body said
Answer:
- The temperature of 10°C will be experienced at an altitude of 2.52 km
- The temperature of 0°C will be experienced at an altitude of 4.15 km
Explanation:
Lapse Rate = -6.5°C/km of ascent.
Lapse Rate = Temperature difference/altitude difference
For the 10°C,
Temperature difference = 10 - 27 = -17°C
-6.5 = -17/(difference in altitude between the two points)
Difference in altitude = 17/6.5 = 2.52 km
For 0°C,
Temperature difference = 0 - 27 = - 27°C
-6.5 = -27/(difference in altitude between the two points)
Altitude difference = 27/6.5 = 4.15 km
You always multiply the mass (kg) by the velocity at which the object is travelling (m/s) to get the momentum (kg m/s) thus: 30 × 5 = 150 kg m/s
