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Step2247 [10]
3 years ago
9

If two objects of unequal mass collide, both objects will continue to move in the direction of

Physics
2 answers:
yarga [219]3 years ago
7 0

Answer:

So what's the answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Explanation:

gayaneshka [121]3 years ago
3 0
Assuming this is an elastic collision, they go in the direction of the object with more mass
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If the range of a projectile's trajectory is six times larger than the height of the trajectory, then what was the angle of laun
zvonat [6]

Answer:

H = 1/2 g t^2    where t is time to fall a height H

H = 1/8 g T^2   where T is total time in air  (2 t  = T)

R = V T cos θ       horizontal range

3/4 g T^2 = V T cos θ       6 H = R    given in problem

cos θ = 3 g T / (4 V)           (I)

Now t = V sin θ / g     time for projectile to fall from max height

T = 2 V sin θ / g

T / V = 2 sin θ / g

cos θ = 3 g / 4 (T / V)     from (I)

cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ

tan θ = 2/3      

θ = 33.7 deg

As a check- let V = 100 m/s

Vx = 100 cos 33.7 = 83,2

Vy = 100 sin 33,7 = 55.5

T = 2 * 55.5 / 9.8 = 11.3 sec

H = 1/2 * 9.8 * (11.3 / 2)^2 = 156

R = 83.2 * 11.3 = 932

R / H = 932 / 156 = 5.97        6 within rounding

3 0
2 years ago
Which point on the graph shows a temperature of 40°C and the time of 25 minutes?
const2013 [10]

Answer:

'A' is the the point on the graph that shows a temperature of 40°C and the time of 25 minutes

8 0
3 years ago
Read 2 more answers
Select the correct answer. The motion of a car on a position-time graph is represented with a horizontal line. What does this in
enyata [817]

If the car's motion appears as a horizontal line on a <u><em>position-time </em></u>graph, it shows that as time changes, the car's position doesn't change.

This is just a complicated way to say that the car is <em>not moving</em>.<em> (A)</em>

7 0
3 years ago
PLEASE HELP !!
Paraphin [41]
Distance from the reference point
7 0
3 years ago
Use the equation of motion to answer the question. Use the equation of motion to answer the question.
satela [25.4K]

The final position of the object after 2 s is 11 m.

Motion: This can be defined as the change in position of a body.

⇒ Formula:

  • x = x₀+v₀t+1/2(at²)........................ Equation 1

⇒ Where:

  • x = Final position of the object
  • x₀ = Starting position
  • v₀ = Starting velocity
  • t = time
  • a = acceleration

From the question,

⇒ Given:

  • x₀ = 4.5 m/s
  • t = 2 s
  • x₀ = 2m
  • a = 0 m/s²

⇒ Substitute these values into equation 1

  • x = 2+(4.5×2)+1/2(0²×2)
  • x = 2+9+0
  • x = 11 m

Hence, The final position of the object after 2 s is 11 m

Learn more about motion here: brainly.com/question/15531840

4 0
2 years ago
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