Answer:
The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.
Explanation:
Using Boyle's law
Given ,
V₁ = 14.65 L
V₂ = 7.94 L
P₁ = ?
P₂ = 5.02 atm
Using above equation as:
<u>The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.</u>
Answer: the beaker with a higher boiling point is B.
Explanation:
since it contains more mass/ volume it takes up more time to heat up.
hope this helps!
Answer:
In the above reaction, sulfur dioxide and oxygen react together to form sulfur trioxide. This means that an increase in pressure would move the equilibrium to the right and result in more sulfur trioxide being formed. Pressure can only affect the position of equilibrium if there is a change in the total gas volume.
Answer:
The answer to your question is FeS₃
Explanation:
Data
mass of Fe = 3.78g
mass of S = 5.95 g
mass of FeS
Chemical Balanced Reaction
Fe + S ⇒ FeS
Process
1.- Convert the grams to moles
For Iron
55.85g of Fe -------------- 1 mol
3.78 g of Fe ----------- x
x = (3.78 x 1) / 55.85
x = 0.0677 moles
For Sulfur
32 g of S ------------------- 1 mol
5.95 g ------------------ x
x = (5.95 x 1)/32
x = 0.185 moles
2.- Divide by the lowest number of moles
Iron = 0.0677 /0.0677 = 1
Sulfur = 0.185 /0.0677 = 2.73 ≈ 3
3.- Write the empirical formula
FeS₃
