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sashaice [31]
3 years ago
12

What measures the amount of energy in a wave ?

Physics
1 answer:
Sliva [168]3 years ago
5 0
Frequency measure the energy in a wave.
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ok so for 99 points(not multiple choice)what is one way to separate salt from grains NO MULTIPLE CHOICE
iragen [17]
Place mixtuer into water. stir mixture into water, wait untill salt is disoldved. Strain out grain. boil water intill only salt is left. Hope this helps! ^-^
6 0
3 years ago
Read 2 more answers
A capacitor with plates separated by a distance d is charged to a potential difference ΔVC. All wires and batteries are disconne
Tom [10]

Answer:

Explanation:

Initial separation of plate = d

final separation = 2d

The capacitance of the capacitor will reduce from C to C/2 because

capacitance = ε A / d

d is distance between plates.

As the batteries are disconnected , charge on the capacitor becomes fixed .

Initial charge on the capacitor

= Capacitance x potential difference

Q = C ΔV

Final charge will remain unchanged

Final charge = C ΔV

Final capacitance = C/2

Final potential difference = charge / capacitance

= C ΔV /  C/2

= 2 ΔV

Potential difference is doubled after the pates are further separated.

6 0
3 years ago
1) Halving the distance (i.s., decreasing by a factor of two) between two charged objects will cause the electrical force betwee
Vedmedyk [2.9K]

Answer:

Explanation:

For an electric force, F the formula:

F = kQq/r^2

Given:

r2 = 1/2 × r1

F1 × r1 = k

F1 × r1 = F2 × r2

F2 = (F1 × r1^2)/(0.5 × r1)^2

= (F1 × r1^2)/0.25r1^2

= 4 × F1.

7 0
4 years ago
hich muscle fibers are best suited for activities that involve lifting large, heavy objects for a short period of time? cardiac
Temka [501]

Answer:

Dead lifting uses tho muscle fundamentals

Explanation:

6 0
4 years ago
During a braking test, a car is brought to rest beginning from an initial speed of 60 mi/hr in a distance of 120 ft. With the sa
maw [93]

Answer:

Explanation:

Given

Initial speed u=60\ mi/hr\approx 88\ ft/s

distance traveled before coming to rest d_1=120\ ft

using equation of motion

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

0-(88)^2=2\times a\times 120---1

for u_2=80\ mi/hr\approx 117.33\ ft/s

using same relation we get

0-(117.33)^2=2\times a\times (d_2)----2

divide 1 and 2 we get

(\frac{88}{117.33})^2=\frac{120}{d_2}

d_2=213.32\ ft

So a distance if 213.32 ft is required to stop the vehicle with 80 mph speed

8 0
3 years ago
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