Answer: 363 Ω.
Explanation:
In a series AC circuit excited by a sinusoidal voltage source, the magnitude of the impedance is found to be as follows:
Z = √((R^2 )+〖(XL-XC)〗^2) (1)
In order to find the values for the inductive and capacitive reactances, as they depend on the frequency, we need first to find the voltage source frequency.
We are told that it has been set to 5.6 times the resonance frequency.
At resonance, the inductive and capacitive reactances are equal each other in magnitude, so from this relationship, we can find out the resonance frequency fo as follows:
fo = 1/2π√LC = 286 Hz
So, we find f to be as follows:
f = 1,600 Hz
Replacing in the value of XL and Xc in (1), we can find the magnitude of the impedance Z at this frequency, as follows:
Z = 363 Ω
Answer:
attracted
Explanation:
Electrons are negative.
A positively charged object will attract a negatively charged object
Answer:
electrons
Explanation:
they go through the wires and power our computer tech
The diagram is labelled to DRAW the RESULTANT wave and LABEL the areas of interference with CI, DI and/or points of TDI.
<h3>What is refraction?</h3>
When a light ray falls on the interface of two medium like air and water, then the portion of light is reflected and another portion of the light is refracted into the water medium. The angle of incidence is equal to the angle of reflection but the angle of incidence is larger then the angle of refraction.
Open the attached file. It shows 2 waves (a blue one and an orange one) that are moving through the same medium at the same time.
Thus, the diagram is labelled.
Learn more about refraction.
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<span>Using ohm’s law, I = V/R. The voltage given is
45 and the resistance is 10 ohms. Substituting the given values in our
equation. We have, I = 45 / 10. Simplify, I = 4.5 amps. The total current in
the circuit is 4.5 amperes </span>