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3 years ago

Select the equation of the line that passes through the point (3, −1) and is perpendicular to the line on the graph.

Mathematics

1 answer:

aniked [119]3 years ago

4 0

I think it would be x=-1

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Luke's favorite cereal is Trix He wants to know how much cereal is actually in the box with measures of cereal box of find the l

weqwewe [10]

Answer:

128 cubic inches

Step-by-step explanation:

4×4×8= 128

8 0

3 years ago

Electric City is having a sale on compact discs. The regular price of $14.00 is decreased by 20%. What is the sale price?

rewona [7]

.20*14.00=2.80
14.00-2.80=11.20

8 0

4 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago

What are the solutions to the system of equations graphed below?

Morgarella [4.7K]

Answer:

looking at the straight line, it touches the axis at (-2,0) and (6,0)

Step-by-step explanation:

6 0

3 years ago

Write a quadratic equation with -4 and 3/2 as it’s roots. Write the equation in the form ax^2 + bx + c = 0, where a, b, and c ar

jonny [76]

9514 1404 393

Answer:

2x² +5x -12 = 0

Step-by-step explanation:

When p and q are roots of a quadratic, its factored form can be written as ...

(x -p)(x -q) = 0

Here, the roots are given as -4 and 3/2, so the factored form would be ...

(x -(-4))(x -(3/2) = 0

Multiplying by 2 gives us ...

(x +4)(2x -3) = 0

Expanding the product, we find the desired quadratic is ...

2x² +5x -12 = 0

5 0

3 years ago