So the equation for angular velocity is
Omega = 2(3.14)/T
Where T is the total period in which the cylinder completes one revolution.
In order to find T, the tangential velocity is
V = 2(3.14)r/T
When calculated, I got V = 3.14
When you enter that into the angular velocity equation, you should get 2m/s
The net force on the sledge is 31.64N.
Frictional force = µkR
= 0.269 x 42.2 x 9.81 = 111.36
net force = 143N - 111.36N
= 31.64N
refer brainly.com/question/24557767
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The gravitational force between the Earth and the satellite (its "weight") is inversely proportional to the distance between the centers of both objects.
On the surface, their centers are separated by 1 Earth radius.
12,000 miles above the surface, they're separated by 4 Earth radiii.
(4/1) = 4
So after the move, the satellite's weight is (1/4²) = 1/16 of its surface weight.
(321 lb) / (16) = (20 and a hair) lb
The correct choice from the given list is " <em>>20 lb "</em> .
Answer:
0.976 c
Explanation:
= velocity of object 1 relative to earth = 0.80 c
= velocity of object 2 relative to object 1 = 0.80 c
= velocity of object 2 relative to earth
Velocity of object 2 relative to earth is given as
= 0.976 c
Sure you can..... ....................
