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3 years ago

What force will accelerate a 20 kg object at 4 m/s 2? *

Physics

1 answer:

bearhunter [10]3 years ago

5 0

Answer:

80 N

Explanation:

mass = 20 kg

acceleration = 4 m/s^2

Force = mass * acceleration

= 20 *4

= 80 N

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A 66-kg bicyclist (including the bicycle) accelerates uniformly from 0.50 m/s to 1.50 m/s, traveling 6.0m. What is the net force

FromTheMoon [43]

The net force acting on the bicyclist is 11.022 Newton.

Given the following data:

Mass of bicyclist = 66 kg

Initial velocity = 0.50 m/s

Initial velocity = 1.50 m/s

Distance traveled = 6.0 meters

To find the net force acting on the bicyclist, we would apply Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by this formula;

$Force = mass$ × $acceleration$

First of all, we would determine the acceleration by using the third equation of motion;

$V^2 = U^2 + 2aS\\\\1.5^2 = 0.5^2 + 2a(6)\\\\2.25 = 0.25 + 12a\\\\12a = 2.25 - 0.25\\\\12a = 2\\\\a = \frac{2}{12}$

Acceleration, a = 0.167 $m/s^2$

Now, we can find the net force acting on the bicyclist:

$Force = 66$ × $0.167$

Force = 11.022 Newton

Therefore, the net force acting on the bicyclist is 11.022 Newton.

Read more here: brainly.com/question/24029674

4 0

2 years ago

Options: Amplitude, crest, trough, wavelength

kompoz [17]

B) amplitude A) crest C) Trough D) wavelength

6 0

3 years ago

How will the world end?

Law Incorporation [45]

Answer:

no one knows

Explanation:

7 0

3 years ago

The following time dependent force is applied to a 2 kg block that is initially at rest on a frictionless and horizontal surface

DerKrebs [107]

Answer:

The displacement of the block is 9 m.

Explanation:

Given that,

Mass of block = 2 kg

Time = 3 sec

The force is

$F(t)=4t$

The acceleration is

$a=\dfrac{F}{m}$

Put the value into the formula

$a=\dfrac{4t}{2}$

$a=2t$

We need to calculate the velocity

Using formula of acceleration

$v=\int_{0}^{t}{a dt}$

Put the value into the formula

$v=\int_{0}^{3}(2t dt)$

$v=(\dfrac{2t^2}{2})_{0}^{3}$

$v=(t^2)_{0}^{3}$

$v=9\ m/s$

We need to calculate the displacement

Using formula of velocity

$s=\int_{0}^{3}(v dt)$

$s=(t^2)_{0}^{3}$

$s=(\dfrac{t^3}{3})_{0}^{3}$

$s=9\ m/s$

Hence, The displacement of the block is 9 m.

8 0

3 years ago

Read 2 more answers

Set up a parallel circuit with three resistors. Set up the battery to be 9 V, one resistor at 10 Ohms, the other at 21 Ohms, and

valina [46]

In a parallel circuit, the equivalent resistance is the reciprocal of (the sum of the individual reciprocals).

1/R = 1/10 + 1/21 + 1/13

1/R = 0.225 mhos

R = 4.45 ohms

I = V / R

The total current out of the battery is

I = (9v)/(4.45ohms)

I = 2.02 Amperes

As the total current leaves the battery, it splits into 3 paths, and each resistor gets part of it. The 10ohm resistor gets the most current; the 21ohm resistor gets the least current. After flowing through the resistors, the 3 currents join and add up to 2.02 Amperes again, and the same current returns to the battery.

Each resistor has the same 9v of EMF across it.

4 0

3 years ago