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Ray Of Light [21]
4 years ago
5

When would the velocity of a wave traveling in a medium change

Physics
2 answers:
netineya [11]4 years ago
7 0
When the property of the medium changes.
MAXImum [283]4 years ago
7 0

Answer:

It depends on the elasticity of the medium

Explanation:

If the travelling wave is a longitudinal wave then the speed of the wave is given by the formula

v = \sqrt{\frac{E}{\rho}}

now we know that if the elastic property of medium or the density of medium will change then the wave will change its velocity

for solids we can say that

E = Y(Young's Modulus)

and for liquids and gases it is given as

E = B(Bulk Modulus)

so we can say that velocity of the wave will change due to change in medium because it depends on elasticity of the medium and its density

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Answer:

A

Explanation:

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3 years ago
A body initially at 100°C cools to 60°C in minutes and to 40°C. The temperature of body at the end of 15 minutes will be​
zhuklara [117]

The question is incomplete, the complete question is;

A body initially at a all 100 degree centigarde cools to 60 degree centigarde in 5 minutes and to 40 degree centigarde in 10 minutes . What is the temperature of surrounding? What will be the temperature in 15 minutes?

Answer:

See explanation

Explanation:

From Newton's law of cooling;

θ1 - θ2/t = K(θ1 + θ2/2 - θo]

Where;

θ1 and θ2 are initial and final temperatures

θo is the temperature of the surroundings

K is the constant

t is the time taken

Hence;

100 - 60/5 = K(100 + 60/2 - θo)

100 - 40/10 = K(100 + 40/2 - θo)

8= (80 - θo)K -----(1)

6= (70 - θo)K -----(2)

Diving (1) by (2)

8/6 = (80 - θo)/(70 - θo)

8(70 - θo) = 6(80 - θo)

560 - 8θo = 480 - θo

560 - 480 = -θo + 8θo

80 = 7θo

θo = 11.4°

Again from Newton's law of cooling;

θ = θo + Ce^-kt

Where;

t= 0, θ = 60° and θo = 11.4°

60 = 11.4 + C e^-K(0)

60 - 11.4 = C

C= 48.6°

To obtain K

40 = 11.4 + 48.6e^-10k

40 -11.4 = 48.6e^-10k

28.6/48.6 = e^-10k

0.5585 = e^-10k

-10k = ln0.5585

k= ln0.5585/-10

K= 0.0583

Hence, the temperature in 15 minutes;

θ= 11.4 + 48.6e^(-0.0583 × 15)

θ= 31.7°

4 0
3 years ago
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Dmitry [639]

The law of reflection states that the angle of incidence and the angle of reflection will always be equal.

When a ray of light reflects off a surface, the angle of reflection is equal to the angle of incidence.

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