Answer:
its either d or a
Explanation:
imma say d looks pretty right though
They relate because the further up you go, the colder it gets, and the air pressure decreases the further up you go. The altitude temperature and the air pressure both decrease, and that is their relationship. Altitude temperature decreases, the higher you go, and air pressure also decreases, the higher up you go. Therefore, the lower down you go, the higher the air pressure, and the higher the altitude temperature.
Hope this helps and have a nice day:)
Answer:
A. Area under force-time graph & Area under force-displacement graph
Explanation:
To find the impulse or work done the area under force-time graph and area under force-displacement graph will give us these respective values.
Impulse = Force x time
Work done = Force x displacement
When we plot a graph of force and time, the area under it is the impulse.
When a graph of force and displacement is plotted, the area under is the work done.
Answer:
a) λ = 2 m
, c) f = 50 Hz
Explanation:
When a string is fixed at the ends the wave is reflected at each end, giving rise to a standing wave.
Since we extract them are fixed we have nodes at these points, the wavelength in the string is
fundamental λ = 2L
2nd harmonic λ= 2L / 2
3 harmonica λ= 2L / 3
a and b) from aui we can find the wavelength
λ = 2 3/3
λ = 2 m
c) the speed of the wave is related to the frequency and wavelength
v = λ f
f = v / λ
f = 100/2
f = 50 Hz
d) the acceleration can be found with the equations
a = d²y / dt²
the standing wave equation is
y = 2A sin kx cos wt
a = -2A w² sin kx cos wt
the acceleration is maximum when the cosine is ±1
A = 2A w² sin kx
the oscillatory part indicates that the wave moves, if we make this maximum vine, they relate it to
a = 2A w²
w = 2πf
A = 0.2 cm = 0.002 m
a = 2 0.002 (2π 50)²
a = 98.7 m / s
Newton's First Law states that when an object is not in motion, it will stay motionless until a force is acted upon it. In this case, you are not moving, so unless a force acts upon you, you will stay in place.