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4 years ago

What is the most stable resonance structure if oxygen is the central atom in the CON– ion?

Chemistry

1 answer:

alexandr1967 [171]4 years ago

8 0

Answer:

The most stable resonance structure shown in fig (II).

Explanation:

Given that,

If oxygen is the central atom in the CON– ion

We know that,

Resonance :

The movement of electron is called resonance.

If the electronegativity is more of element then the element is more stable.

We need to find the most stable resonance structure

According to figure,

Electronegativity of N is more than C

So, N is the more stable in fig (II).

Hence, The most stable resonance structure shown in fig (II).

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90 POINTSSSS!!!

Katarina [22]

Answer:

$\large \boxed{\text{-2043.96 kJ/mol}}$

Explanation:

Assume the reaction is the combustion of propane.

Word equation: propane plus oxygen produces carbon dioxide and water

Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)

Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)

(a) Table of enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}$

(b)Total enthalpies of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\= \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}$

ΔᵣH° is negative, so the reaction is exothermic.

5 0

3 years ago

The distance traveled divided by the time taken to travel the distance is _

BigorU [14]

Speed is the distance traveled divided by the time. This can also be written as $Speed = \frac{Distance}{Time}$ . Hope this helped!

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4 years ago

Which of the pairs of compounds below could be used to prepare a buffer solution? hcl and nacl hc2h3o2 and kc2h3o2 nh3 and nh4no

Basile [38]

We have that the correct answer is the last one. NH4NO3 is called ammonium nitrate and is the salt that appears from combining HNO3 (acid) with NH3 (ammonia, base). We have then that a solution of this type is a buffer solution because ammonia is a weak base and the salt contains its conjugate acid (definition of buffer solution). The 2nd example is wrong because both potassium acetate and Acetic Acid are acids; no conjugate base is involved. HCI and NaCl are pairs of conjugacy (HCI is an acid and NACI can be produced by NaOH and HCI), but HCI is a strong acid and NACI is a salt. Hence, it cannot be a buffer solution (weak acid needed). Weak acid or base means that it does not fully break down in ions when in water.

8 0

4 years ago

A 23.5g aluminum block is warmed to 65.9°C and plunged into an insulated beaker containing 55.0g water initially at 22.3°C. The

atroni [7]

Answer:

25.97oC

Explanation:

Heat lost by aluminum = heat gained by water

M(Al) x C(Al) x [ Temp(Al) – Temp(Al+H2O) ] = M(H2O) x C(H2O) x [ Temp(Al+H2O) – Temp(H2O) ]

Where M(Al) = 23.5g, C(Al) = specific heat capacity of aluminum = 0.900J/goC, Temp(Al) = 65.9oC, Temp(Al+H2O)= temperature of water and aluminum at equilibrium = ?, M(H2O) = 55.0g, C(H2O)= specific heat capacity of liquid water = 4.186J/goC

Let Temp(Al+H2O) = X

23.5 x 0.900 x (65.9-X) = 55.0 x 4.186 x (X-22.3)

21.15(65.9-X) = 230.23(X-22.3)

1393.785 - 21.15X = 230.23X – 5134.129

230.23X + 21.15X = 1393.785 + 5134.129

251.38X = 6527.909

X = 6527.909/251.38

X = 25.97oC

So, the final temperature of the water and aluminum is = 25.97oC

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3 years ago

How is burning methane similar to burning magnesium?

zvonat [6]

I think it is that they use the same process which is oxidation

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3 years ago

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