We have that the instantaneous velocity of the
shuttlecock when it hits the ground is

From the question we are told
Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the
shuttlecock when it hits the ground? Show your work below.
Generally the equation for acceleration is mathematically given as

Where
acceleration is still -9.81 m/s2,
Hence,

Therefore

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Answer: Cross-cutting features are always younger than the surrounding rock.
When material erodes before sediment is deposited on it, a geologic gap results.
Explanation:
The options include:
1. An unconformity is created when lava pours out on Earth’s surface.
2. Faults are the result of volcanic activity.
3. Intrusions and extrusions are sedimentary formations.
4. Cross-cutting features are always younger than the surrounding rock.
5. When material erodes before sediment is deposited on it, a geologic gap results.
The law of superposition simply states that when there is a layers of rocks, we would see that the younger layers will lie and be on top of the layers that are older.
Other tools that can help scientist with relative dating are:
• Cross-cutting features are always younger than the surrounding rock.
• When material erodes before sediment is deposited on it, a geologic gap results.
The conventional signal used by sailboats in conditions of reduced visibility such as heavy fog is one long blast followed by two short blasts.
The blasts help other boat operators locate one another's vessel in a condition where it is not easy to see. This signal is repeated in order to not only let others know of the vessel's position, but also help them know which way it is traveling. For example, if the blasts start to become distant, then the sailboat is travelling away from you.
Answer:
Distance covered by B is 4 times distance covered by A
Explanation:
For an object in free fall starting from rest, the distance covered by the object in a time t is

where
s is the distance covered
g is the acceleration due to gravity
t is the time elapsed
In this problem:
- Object A falls through a distance
during a time t, so the distance covered by object A is

- Object B falls through a distance
during a time 2t, so the distance covered by object B is

So, the distance covered by object B is 4 times the distance covered by object A.
Answer:
a. El tiempo de recorrido es
segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.
b. El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.
Explanation:
El sonido es un tipo de onda mecánica, que es un tipo de onda que necesita de un medio material para propagarse. En este caso, entendemos que el sonido se propaga a través del aire atmosférico hasta llegar a su destino y devolverse a rapidez constante. Entonces, podemos estimar el tiempo (
), medido en segundos, a partir de la siguiente fórmula:

Donde:
- Distancia entre la cámara fotográfica y el objeto, medida en metros.
- Rapidez del sonido en el aire atmosférico, medida en metros por segundo.
A continuación, calculamos el tiempo de recorrido:
a. (
,
)


El tiempo de recorrido es
segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.
b. (
,
)


El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.