Which determines the reactivity of an alkali metal?
1 answer:
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Answer:
Explanation:
Given
initially mass is stretched to
Let k be the spring Constant of spring
Therefore Total Mechanical Energy is
Position at which kinetic Energy is equal to Elastic Potential Energy
it is given
thus
Considering conservation of mechanical energy we have:
K+U (start)= K+U (end)
Where:
K=kinetic energy=
U=potential energy=
So:
0.05*0.95*9.81+0 (start) = 0+K (end)
K (end)=0.5 Joules
K+U (start)= K+U (end)
Where:
K=kinetic energy=
U=potential energy=
So:
0.05*0.95*9.81+0 (start) = 0+K (end)
K (end)=0.5 Joules