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zimovet [89]
3 years ago
6

How can endurance athletes best delay muscle fatigue during training? a. By avoiding sports drinks during exercise b. By eating

glucose periodically during the event c. By staying in the moderate intensity range to prevent anaerobic metabolism d. By consuming excess fat three days before the event e. By reducing their body fat to less than 5 percent of the total body weight
Engineering
2 answers:
lys-0071 [83]3 years ago
5 0

Answer:

Option C

By staying in the moderate intensity range to prevent anaerobic metabolism

Explanation:

Endurance athletes best delay muscle fatigue during training by staying in the moderate intensity range to prevent anaerobic metabolism

nikklg [1K]3 years ago
4 0

Answer:

The correct answer is B. Endurance athletes can best delay muscle fatigue during training by eating glucose periodically during the event.

Explanation:

Glucose is one of the most important carbohydrates and is used as an energy source by animals and plants, as it is by far the most common monosaccharide. Glucose is also a building block of starch, cellulose and glycogen polysaccharides.  For this reason it is recommended that, during intense physical exercise sessions, athletes consume high-glucose food rations, so as not to deplete their carbohydrate stores and therefore continue to have available energy to carry out their routines.

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Fatigue failure occurs under the condition of (a) High elastic stress (b) High corrosivity (c) High stress fluctuations (d) High
Harlamova29_29 [7]

Answer:

Fatigue occurs under conditions of high elastic stress, high stress fluctuations and high rate of loading

Explanation:

 According to many definition of fatigue failure the fatigue occurs when in an especifyc point of the object there is involved many forces and tensions.

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4 years ago
In which of the following states would homes most likely have the deepest foundation?
Evgen [1.6K]

Answer:

D) Louisiana, to prevent homes from blowing away in hurricanes.

Explanation:

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5 0
2 years ago
A 100 ft long steel wire has a cross-sectional area of 0.0144 in.2. When a force of 270 lb is applied to the wire, its length in
blondinia [14]

Answer:

(a) The stress on the steel wire is 19,000 Psi

(b) The strain on the steel wire is 0.00063

(c) The modulus of elasticity of the steel is 30,000,000 Psi

Explanation:

Given;

length of steel wire, L = 100 ft

cross-sectional area, A = 0.0144 in²

applied force, F = 270 lb

extension of the wire, e = 0.75 in

<u>Part (A)</u> The stress on the steel wire;

δ = F/A

   = 270 / 0.0144

δ  = 18750 lb/in² = 19,000 Psi

<u>Part (B)</u> The strain on the steel wire;

σ = e/ L

L = 100 ft = 1200 in

σ = 0.75 / 1200

σ = 0.00063

<u>Part (C)</u> The modulus of elasticity of the steel

E = δ/σ

   = 19,000 / 0.00063

E = 30,000,000 Psi

4 0
3 years ago
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