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Zepler [3.9K]
3 years ago
10

A sequence starts 0,5 give a rule that sequence could follow and the next 3 terms for that rule

Mathematics
1 answer:
balu736 [363]3 years ago
3 0

Answer:

hey did you ever found the answer because i need help with this question too

Step-by-step explanation:

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Identify the solution set of 3 In 4 = 2 In x.<br> -{6}<br> -{-8,8}<br> -(8)
o-na [289]

Option C: The solution set is \{8\}

Explanation:

The expression is 3 \ln 4=2 \ln x

Now, let us find the solution set.

Switch sides, we get,

2 \ln x=3 \ln 4

Dividing by 2 on both sides, we have,

\ln x=\frac{3 \ln 4}{2}

Thus,  \ln 4=\ln 2^2=2\ln 2

Hence, the above expression becomes,

\ln x=\frac{3 \cdot 2 \ln (2)}{2}

Simplifying, we get,

\ln x=3 \ln 2

Applying the log rule, we get,

$$\ln x$=\ln \left(2^{3}\right)$

Simplifying, we have,

$$\ln x$=\ln \left8\right$

Applying the log rule, we have,

x=8

Thus, the solution set is \{8\}

Hence, Option C is the correct answer.

5 0
3 years ago
For each value of u, determine whether it is a solution to -15 = 1 - 4u
Alona [7]

Answer:

1. No

2. No

3. No

4. Yes

Step-by-step explanation:

Plug each option into u then solve the equation and see if the answer matches -15.

Ex. -15 = 1 -4 (2)

     -15 = 1 -8

     -15 = -7

     -15 does not equal -7 therefore it is false. Use Pemdas to solve.

6 0
3 years ago
Classify the absolute value statements based on their values. |3| |-3| |-4| |4| |-5| |5|
Fittoniya [83]
The answers would be 3, 3, 4, 4, 5, 5. those are the answers. I don't know if that is what you wanted me to answer or not.
5 0
3 years ago
Read 2 more answers
7th grade math help me plzzzz
Nataly_w [17]

Answer:

<h3>The correct answer is <u>D: -30</u></h3>
5 0
2 years ago
Read 2 more answers
Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )
DedPeter [7]
(a) First find the intersections of y=e^{2x-x^2} and y=2:

2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}

So the area of R is given by

\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx

If you're not familiar with the error function \mathrm{erf}(x), then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line y=1 with y=e^{2x-x^2}.

1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2

So the area of S is given by

\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx
\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve y=e^{2x-x^2} and the line y=1, or e^{2x-x^2}-1. The area of any such circle is \pi times the square of its radius. Since the curve intersects the axis of revolution at x=0 and x=2, the volume would be given by

\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx
5 0
3 years ago
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