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Alexxandr [17]
3 years ago
11

Write two examples of chemical properties and explain what they are

Physics
1 answer:
Gre4nikov [31]3 years ago
6 0
Chemical Properties are properties of a substance that are seen during a chemical reaction. In other words, chemical properties cannot be found by looking/touching the substance. Those are its physical properties.

Examples

Flammability
toxicity
solubility
Acidity
Electronegativity
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Suppose a police officer is 1/2 mile south of an intersection, driving north towards the intersection at 40 mph. At the same tim
blagie [28]

Answer:

75.36 mph

Explanation:

The distance between the other car and the intersection is,

x=x_{0}+V t \\ x=\frac{1}{2}+V t

The distance between the police car and the intersection is,

y=y_{0}+V t

y=\frac{1}{2}-40 t

(Negative sign indicates that he is moving towards the intersection)

Therefore the distance between them is given by,

z^{2}=x^{2}+y^{2}(\text { Using Phythogorous theorem })

z^{2}=\left(\frac{1}{2}+V t\right)^{2}+\left(\frac{1}{2}-40 t\right)^{2} \ldots \ldots \ldots(1)

The rate of change is,

2 z \frac{d z}{d t}=2\left(\frac{1}{2}+V t\right) V+2\left(\frac{1}{2}-40 t\right)(-40)

2 z \frac{d z}{d t}=V+2 V^{2} t-40+3200 t \ldots \ldots \ldots

Now finding z when t=0, from (1) we have

z^{2}=\left(\frac{1}{2}+V(0)\right)^{2}+\left(\frac{1}{2}-40(0)\right)^{2}

z^{2}=\frac{1}{4}+\frac{1}{4}=\frac{1}{2} \\ z=\sqrt{\frac{1}{2}} \approx 0.7071

The officer's radar gun indicates 25 mph pointed at the other car then, \frac{d z}{d t}=25 when t=0, from

From (2) we get

2(0.7071)(25)=V+2 V^{2}(0)-40+3200(0)

2(0.7071)(25)=V+2 V^{2}(0)-40

35.36=V-40

V=35.36+40=75.36

Hence the speed of the car is 75.36 mph

7 0
3 years ago
Technician A says that the intake and exhaust manifolds have to be removed before removing the engine from the vehicle. Technici
Amiraneli [1.4K]

Answer: Technician A is correct

Explanation:

The intake manifold is the compactment that all fuel and air supply to the cylinders. It's connected to the engine so it has to be disconnected while the exhaust manifold receives all the exhaust gases from the cylinders and releases the gas through a single or double exhaust gases outlet.

5 0
3 years ago
Gas liquids will both expand to fll their containers true or false
MrMuchimi
It Is False. Liquid will not expand to fill it's container, while gas will. 

6 0
3 years ago
A proposed space station consists of a circular tube that will rotate about its center (like a tubular bicycle tire), Fig. 5–39.
Trava [24]

Answer:

1742.24106 revolutions per day

Explanation:

v = Velocity

d = Diameter = 1.1 km

r = Radius = \dfrac{d}{2}=\dfrac{1.1}{2}=0.55\ km

g = Acceleration due to gravity = 9.81 m/s²

g = 0.9 g

The centrifugal force will balance the gravitational force

F_c=mg\\\Rightarrow \dfrac{mv^2}{r}=m0.9g\\\Rightarrow v=\sqrt{\dfrac{0.9gmr}{m}}\\\Rightarrow v=\sqrt{0.9gr}\\\Rightarrow v=\sqrt{0.9\times 9.81\times 0.55\times 10^3}\\\Rightarrow v=69.68464\ m/s

\dfrac{1}{T}=\dfrac{v}{2\pi r}\\\Rightarrow \dfrac{1}{T}=\dfrac{69.68464}{2\pi 0.55\times 10^3}\times 24\times 60\times 60\\\Rightarrow \dfrac{1}{T}=1742.24106\ rev/day

The rotation speed is 1742.24106 revolutions per day

6 0
3 years ago
Read 2 more answers
Find the gravitational potential at a point on the earth surface. Take mass as of earth as 5.98×10^24kg,it's radius as6.38×10^6n
andrew-mc [135]

Answer:

-6.25\cdot 10^7 J

Explanation:

The gravitational potential at a point on the Earth surface is given by:

U=-\frac{GM}{R^2}

where

G=6.67×10^-11Nm^2kg^-2 is the gravitational constant

M=5.98×10^24kg is the Earth's mass

R=6.38×10^6 m is the Earth's radius

Substituting the numbers into the equation, we find

U=-\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.38\cdot 10^6)}=-6.25\cdot 10^7 J

5 0
3 years ago
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