The magnitude of the force each hook exerts on the chain is 22.2N.
<h3>Solution:</h3>
Horizontal force on one half of the chain
cos 42° = 
sin 42° = 20
= 29.9N
Now,
= 22.2N
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Because it doesn't have anything to change the temp.
The work done by the stick on the hockey puck is equal to the magnitude of the force times the distance covered by the puck:

And the power of the stick is equal to the ratio between the work done and the time taken, therefore
Potential energy, is energy due to its position.
Given: Mass m = 40 Kg; Height h = 50 m
Required: Potential energy P.E = ?
Formula: P.E = mgh P.E = (40 Kg)(9.8 m/s²)(50 m)
P.E = 19,600 J