ANSWER:
The answer will be OT
Answer:
the number density of the protons in the beam is 3.2 × 10¹³ m⁻³
Explanation:
Given that;
diameter D = 2.0 mm
current I = 1.0 mA
K.E of each proton is 20 MeV
the number density of the protons in the beam = ?
Now, we make use of the relation between current and drift velocity
I = MeAv ⇒ 1 / eAv
The kinetic energy of protons is given by;
K = v²
v = √( 2K / )
lets relate the cross-sectional area A of the beam to its diameter D;
A = πD²
now, we substitute for v and A
n = I / πeD² ×√( 2K / )
n = 4I/π eD² × √( / 2K )
so we plug in our values;
n = ((4×1.0 mA)/(π(1.602×10⁻¹⁹C)(2mm)²) × √(1.673×10⁻²⁷kg / 2×( 20 MeV)(1.602×10⁻¹⁹ J/ev )
n = 1.98695 × 10¹⁸ × 1.6157967 × 10⁻⁵
n = 3.2 × 10¹³ m⁻³
Therefore, the number density of the protons in the beam is 3.2 × 10¹³ m⁻³
Answer:
500 kW
Explanation:
Given that,
Energy of the train, E = 2 MJ = 2×10⁶ J
Time, t = 4 seconds
We need to find the power of the train. We know that,
Power = energy/time
So,
So, the power of the train is equal to 500 kW.
Answer:
a) B = 0.9375 T -z, b) B = 1.54 T
Explication
a) The magnetic force is
F = q v x B
f = q v B sin θ
bold indicates vectors
For direction let's use the right hand rule.
If the charge is positive
the flea in the direction of velocity, toward + x
the fingers extended in the direction of B
the palm the direction of the force + and
therefore the magnetic field goes in the direction of -z
F = q v B
2.25 10-16 = 1.6 10-19 1.50 103 B
B = 2.25 10-16 / 2.4 10-16
B = 0.9375 T -z
b) now an electron
thumb speed direction, -z
opposite side of palm force + y
therefore the direction of the magnetic field is + x
B = F / qv
B = 8.5 10-16 / 1.16 10-19 4.75 103
B = 1.54 T
<h2>
Hello!</h2>
The answer is:
The voltage of the source is 8.40 Volts.
<h2>
Why?</h2>
To solve the problem, we need to use the Ohm's Law equation, which states that:
From the statement we know that:
Now, substituting and calculating we have:
Hence, we have that the voltage of the source is 8.40 Volts.
Have a nice day!