Answer: ro= 0.113
Explanation:
Data Given: Where D= Outer diameter
d= Inner diameter
ri= 0.4cm
r°= ?
Charge 1 and Charge 2 (q) = K i.e constant of proportionality
Where K = 1/4πe°. er; 3.2, ep; 2.6 ( Relative permeability)
(a) Approximate value size for the coaxial cable
C= 7.354 x Er/ Log 10 (D÷d)
C = 7.354 x 3.2/ Log 2.6
= 23.5/0.419
= 56.0cm
(b) Outer radius r° when dealing with 20kv
r°= impedance value (pie ÷ 20) d^2
r° = 2( π÷20)0.6^2
= 2( 0.1571) 0.36
r° = 0.113
(c) Assuming The Maximum Electric Field; Fmax = 25%
Given Vin = 25x10^6v/m, Vout = 20x 10^6 v/m.
Impedance p= √Vin x vout/ Z° (i)
Where Z° = electric surge ~25%
Subtituting Value of Vin & Vout In Equation (i)
P = 2.05x10^-8ohms
Note : Length of a conducting material determines the strength of dielectric material between the coaxial cable
Answer: b)Gases
Explanation: Because the Particle are moving freely
Answer:
I_total = L² (m + M / 3)
Explanation:
The moment of inertia is defined by
I = ∫ r² dm
It is appreciated that it is a scalar quantity, for which it is additive, in this case the system is formed by two bodies and the moment of inertia must be the sum of each moment of inertia with respect to the same axis of rotation.
The moment of inertia of a bar with respect to an axis that passes through ends is
I_bar = 1/3 M L²
The moment of inertia of a particle is
I_part = m x²
We have to assume the point where the particle sticks to the bar, suppose it sticks to the end
x = L
Total moment of inertia is the sum of these two moments of inertia
I_total = I_bar + I_particule
I_total = 1/3 M L² + m L²
I_total = L² (m + M / 3)
Ultraviolet radiation from the sun is controlled by the ozone but if it infiltrates into the atmosphere it becomes a hazard. The uv reaches our eyes and darkens the retina and blurs vision. The fovea becomes insensitive and the cells dormant. This causes gradual blindness.
Answer:
The range of wavelengths of the sound is 7692.30 m and 3846.15 m
Explanation:
A bat emits pulses of sound at a frequency between 39 kHz and 78 kHz. It is required to find the range of wavelengths of this sound.
Bat uses ultrasonic waves. It moves with the speed of light.
If f = 39 kHz,
If f = 78 kHz,
So, the range of wavelengths of the sound is 7692.30 m and 3846.15 m.