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stiv31 [10]
2 years ago
9

©

Physics
1 answer:
Andru [333]2 years ago
8 0

Answer:

Two positively charged particles

Explanation:

I said two positively charged particles because if I say c or d what ever it is for you guy it can be wrong so just pick the one that says Two positively charged particles

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What is the wavelength of a 2.50-kilohertz sound
Alexxx [7]
The formula v=fλ can be used here.

326=2500*λ

Note the 2500 as 2.5kHz is 2.5 thousand Hz.

λ = 326/2500
= 0.1304m = 0.130m
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3 years ago
Answer:<br> 1m Up + 5m Left + 2m Down
Natali [406]
Oh ok that is v cool
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3 years ago
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Explain how itis possible for electron-group geometry to difer trom molecular geometry. Use the Lewis dot diagram below to help
Viktor [21]

Answer:

If lone pairs of electrons, electrons not bonded to other atoms, are located in the molecule, this will change the molecular geometry, not the electron geometry. If all the electron groups are bonded, with no lone pairs, then the electron geometry and molecular geometry are the same.

5 0
3 years ago
Two ice skaters collide on the ice. A 39.6-kg skater moving South at 6.21 m/s collides with a 52.1-kg skater moving East at 4.33
Stells [14]

Answer:

V = 3.6385 m/s

θ = 47.46 degrees

Explanation:

the important data in the question is:

Skater 1:

M_1= 39.6 kg

direction: south (axis y)

V_{1iy} = 6.21 m/s

Skater 2:

M_2 = 52.1 kg

direction: east (axis x)

V_{2ix} = 4.33 m/s

Now using the law of the conservation of linear momentum ( P_i = P_f and knowing that the collision is inelastic we can do the next equations:

M_{1}V_{1ix}+M_2V_{2ix} = V_{sx}(M_1+M_2)  (eq. 1)

M_{1}V_{1iy}+M_2V_{2iy} = V_{sy}(M_1+M_2)  (eq. 2)

Where V_{sx} and V_{sy} is the velocity of the sistem in x and y after the collision.

Note: the conservation of the linear momentum have to be make once by each axis.

Now, in the (eq. 1) the skater 1 don't have velocity in the axis x, so we can replace V_{1ix} by 0 in the equation and get:

M_2V_{2ix} = V_{sx}(M_1+M_2)  (eq. 1)

also, in the (eq. 2) the skater 2 don't have velocity in the axis y, so we can replace V_{2iy} by 0 in the equation and get:

M_{1}V_{1iy} = V_{sy}(M_1+M_2)  (eq. 2)

Now, we just replace the data in both equations:

(52.1)(4.33) = V_{sx}(39.6+52.1)  (eq. 1)

(39.6)(6.21) = V_{sy}(39.6+52.1)  (eq. 2)

solving for V_{sx] and V_{sy} we have:

V_{sx] = 2.46 m/s

V_{sy] = 2.681 m/s

using the pythagoras theorem we can find the magnitude of the velocity as:

V = \sqrt{2.46^2+2.681^2}

V = 3.6385 m/s

For find the direction we just need to do this;

θ = tan^{-1}(\frac{2.681}{1.46})

θ = 47.46 degrees

                     

 

3 0
3 years ago
If a car is going faster will the reaction time alter? Explain your answer please
emmasim [6.3K]
Reaction time will stay the same for each person however the faster the car is going the faster someones reaction time would need to be react to something that happened.  therefore it might seem like someone had a slower reaction time when a car is moving faster because everything happens faster when you are moving faster

I hope I've helped!
4 0
3 years ago
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