Answer:
1. I went to the library to study last night.
2.Helen borrowed my dictionary to look up the spelling of "occurred."
3.The teacher opened the window to let some fresh air into the room.
4..I came to this school to learn English.
5.I traveled to Osaka to visit my sister.
Explanation:
...
Answer:
Yes, fracture will occur
Explanation:
Half length of internal crack will be 4mm/2=2mm=0.002m
To find the dimensionless parameter, we use critical stress crack propagation equation
and making Y the subject
Where Y is the dimensionless parameter, a is half length of crack, K is plane strain fracture toughness, is critical stress required for initiating crack propagation. Substituting the figures given in question we obtain
When the maximum internal crack length is 6mm, half the length of internal crack is 6mm/2=3mm=0.003m
and making K the subject
and substituting 260 MPa for while a is taken as 0.003m and Y is already known
Therefore, fracture toughness at critical stress when maximum internal crack is 6mm is 42.455 Mpa and since it’s greater than 40 Mpa, fracture occurs to the material
Answer:
speed(0)
square_length = int(input("What is the length of the square?"))
def draw_square():
pendown()
for i in range(4):
forward(square_length)
left(90)
penup()
penup()
setposition(-200, -200)
draw_square()
penup()
setposition(-200, 200 - square_length)
draw_square()
penup()
setposition(200 - square_length, 200 - square_length)
draw_square()
penup()
setposition(200 - square_length, -200)
draw_square()Explanation:
Answer:
Both Technician A and B are correct
Explanation:
Due to a contamination of the clutch disc friction surface, the clutch chatters
The contamination that causes clutch chattering includes
1) Worn or broken motor mounts
2) Bell housing bolts becoming loose
3) Clutch link damage
4) Warped flywheel, due to overheating, the flywheel can become warped such that the non uniform surface interfaces the clutch resulting in clutch chattering
5) Engine or transmission oil contaminating the disc.
Answer:
Explanation:
Given that:
f = 250 Hz
= 2%
= 600 Hz
= 0.5 to 1.5 increment by 0.05
For 250 Hz = 250 cycle/sec
M = 0.98 , 1.02
At 0.7183 value of damping ratio the error value was 2% at 0.98 value of M
At 0.6330 value of damping ratio the error value was 2% at 1.02 value of M.
Hence, the damping ratio of the transducer must be placed between 0.6330 to 0.7183