Question

6, P 14 are consecutive terms in an APfind the value of P.​

Answer 1

In an arithmetic progression, consecutive terms differ by the same value.

So, we have

$P-6 = 14-P$

which reflects the fact that the difference between P and 6 must be the same than the one between P and 14.

The equation solves to

$2P=20\iff P=10$

And in fact, if you start with

$6, 10, 14$

every pair of consecutive terms differ by 4.